A. 6a2 cm2
B. 8a2 cm2
C. 12a2 cm2
D. 24a2 cm2
Explanation:
6a2 = 6 * 2a * 2a = 24a2
A. 10
B. 15
C. 20
D. 25
Explanation:
Let the bought x pairs of brown socks and the price of each brown pair be Y.
Then total cost = 5x3Y+xy
Changed cost = 5xY+x*3Y
According to the question .
5y+3xy –(15y+xy)/15y+xy x 100% = 100%
=> 5y+3xy-15y-xy/ 15y+xy x100% = 100%
=> 5y+3xy = 15y+xy+15y+xy
=> 5y+3xy = 30y+2xy
=> xy= 25y
=> x=25.
Hence the original pair of brown socks = 25.
A. 10 litres
B. 15 litres
C. 66 2/3 litres
D. 20 litres
Explanation:
Let the capacity of the bucket be x liters
(80% of x) – (200/3% of x) = 2
=> (80/100 × x) – (200/300 × x) = 2
=> 4x/5 – 2x/3 = 2
=> (12x -10x) = 30
=> 2x = 30
=> X = 15 Litres
A. 4
B. 6
C. 8
D. 12
Explanation:
Let the required numbers be 33a and 33b.
Then, 33a + 33b = 528 => a + b = 16.
Now, co-primes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).
Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).
The number of such pairs is 4.
A. 17 hours
B. 12 hours
C. 16 hours
D. 24 hours
Explanation:
The part of the tank filled by three pipes in one hour = 1/8
=> The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.
The tank can be filled in 12 hours.
A. Rs.60000
B. Rs.75000
C. Rs.68400
D. Rs.78400
A. 104
B. 114
C. 315
D. 325
Let the numbers be x and y. Then, x + y = 25 and x – y = 13.
4xy = (x + y)2 – (x – y)2 = (25)2 – (13)2 = 625- 169 = 456
=> xy = 114.