The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
		A. Rs.3000
B. Rs.3300
C. Rs.3600
D. Rs.3900
		A. Rs.3000
B. Rs.3300
C. Rs.3600
D. Rs.3900
		A. Rs 50
B. Rs 60
C. Rs 61
D. Rs 600
Explanation:
S.I = Rs(8000 × 5/100 ×3) = Rs 1200
C.I = Rs [8000 × (1+5/100)3– 8000
= Rs [(8000 × 21/20×21/20×21/20)-8000]
=Rs (9261-8000)=Rs 1261
 (c.I)-(S.I) = Rs (1261 – 1200) = Rs61.
		A. 1
B. 10
C. 12.5
D. 50
Explanation:
5 * 46 – 4 * 45 = 50
Origin lies on the intersection of the x-axis and y-axis, i.e, (0,0).
Greek Mathematics. Euclid enters history as one of the greatest of all mathematicians and he is often referred to as the father of geometry. The standard geometry most of us learned in school is called Euclidian Geometry.
		A. (mb – nc)/ (m + n) years
B. (mb + nc)/ (m – n) years
C. (mb + nc)/ (m + n) years
D. (mb – nc)/ (m – n) years
		A. 10
B. 8
C. 18
D. 19
Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 10 days = 10 × (1/16) = 10/16 = 5/8
Remaining work = 1 = 5/8 = 3/8
Work done by P in 1 day = Work done by P,Q and R in 1 day – Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/8) / (1/48) = 18