The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
		A. 120 sq m
B. 300 sq m
C. 150 sq m
D. 480 sq m
1/2 * 15 * 20 = 150
		A. 120 sq m
B. 300 sq m
C. 150 sq m
D. 480 sq m
1/2 * 15 * 20 = 150
		A. 71
B. 70
C. 69
D. 68
Explanation:
LCM = 72
72 – 3 = 69
		A. Rs.81.60
B. Rs.160
C. Rs.1081.60
D. Rs.99
Explanation:
SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6
		A. Rs.4400
B. Rs.4445
C. Rs.4460
D. Rs.4520
Explanation:
Sum be P
P(1 + R/100)3 = 6690 – (i)
 P(1 + R/100)2 = 10, 035 – (ii)
 By dividing (i) and (ii)
(1 + R/100)3 = 10035/6690 = 3/2
Therefore, P = (6690 x 2/3) = Rs. 4460
		A. 200 sec
B. 190 sec
C. 210 sec
D. 150 sec
Explanation:
Time taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.
Time taken by A = 200 – 10 = 190 sec.
		A. 9:1
B. 4:7
C. 7:1
D. 2:5
Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 – 6 = 6 liters
Remaining water = 8 – 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 – 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
		A. 7
B. 5
C. 6
D. 4
Work done by 10 men in 1 day = 1/7
Work done by 1 man in 1 day = (1/7)/10 = 1/70
Work done by 10 women in 1 day = 1/14
Work done by 1 woman in 1 day = 1/140
Work done by 5 men and 10 women in 1 day = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
=> 5 men and 10 women can complete the work in 7 days