The fourth proportional to 5, 8, 15 is:
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
| x = | (8 x 15) | = 24. |
| 5 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
| x = | (8 x 15) | = 24. |
| 5 |
[B].
[C].
[D].
Answer: Option D
Explanation:
| Quantity of milk = | 60 x | 2 | litres = 40 litres. | |
| 3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
| Then, milk : water = | 40 | . | ||
| 20 + x |
| Now, | 40 | = | 1 | ||
| 20 + x | 2 |
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
[B].
[C].
[D].
Answer: Option C
Explanation:
| Let 40% of A = | 2 | B |
| 3 |
| Then, | 40A | = | 2B |
| 100 | 3 |
| 2A | = | 2B | |
| 5 | 3 |
| A | = | 2 | x | 5 | = | 5 | |||
| B | 3 | 2 | 3 |
A : B = 5 : 3.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
[B].
[C].
[D].
Answer: Option C
Explanation:
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
| 120 | x 7x | and | 110 | x 8x | |||||
| 100 | 100 |
| 42x | and | 44x | |
| 5 | 5 |
| The required ratio = | 42x | : | 44x | = 21 : 22. | ||
| 5 | 5 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
| 140 | x 5x | , | 150 | x 7x | and | 175 | x 8x | |||||||
| 100 | 100 | 100 |
| 7x, | 21x | and 14x. |
| 2 |
| The required ratio = 7x : | 21x | : 14x |
| 2 |
14x : 21x : 28x
2 : 3 : 4.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the third number be x.
| Then, first number = 120% of x = | 120x | = | 6x |
| 100 | 5 |
| Second number = 150% of x = | 150x | = | 3x |
| 100 | 2 |
| Ratio of first two numbers = | 6x | : | 3x | = 12x : 15x = 4 : 5. | ||
| 5 | 2 |
[B].
[C].
[D].
Answer: Option B
Explanation:
| 4 | A | = | 2 | B | |
| 15 | 5 |
| A = | 2 | x | 15 | B | |
| 5 | 4 |
| A = | 3 | B |
| 2 |
| A | = | 3 | |
| B | 2 |
A : B = 3 : 2.
| B’s share = Rs. | 1210 x | 2 | = Rs. 484. | ||
| 5 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = | 5 x | 3 | : | 8 x | 3 | = 3 : | 24 | ||||
| 5 | 5 | 5 |
| A : B : C = 2 : 3 : | 24 | = 10 : 15 : 24 |
| 5 |
| B = | 98 x | 15 | = 30. | ||
| 49 |
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
| Then, | 2x + 4000 | = | 40 |
| 3x + 4000 | 57 |
57(2x + 4000) = 40(3x + 4000)
6x = 68,000
3x = 34,000
Sumit’s present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38,000.