(51 + 52 + 53 + … + 100) = ?
[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
Sn = (1 + 2 + 3 + … + 50 + 51 + 52 + … + 100) – (1 + 2 + 3 + … + 50)
| = | 100 | x (1 + 100) – | 50 | x (1 + 50) |
| 2 | 2 |
= (50 x 101) – (25 x 51)
= (5050 – 1275)
= 3775.
[B].
[C].
[D].
Answer: Option D
Explanation:
Sn = (1 + 2 + 3 + … + 50 + 51 + 52 + … + 100) – (1 + 2 + 3 + … + 50)
| = | 100 | x (1 + 100) – | 50 | x (1 + 50) |
| 2 | 2 |
= (50 x 101) – (25 x 51)
= (5050 – 1275)
= 3775.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let Sn = (2 + 4 + 6 + … + 30). This is an A.P. in which a = 2, d = 2 and l = 30
Let the number of terms be n. Then,
a + (n – 1)d = 30
2 + (n – 1) x 2 = 30
n = 15.
| Sn = | n | (a + l) | = | 15 | x (2 + 30) = (15 x 16) = 240. |
| 2 | 2 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Required numbers are 102, 108, 114, … , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then,
a + (n – 1)d = 996
102 + (n – 1) x 6 = 996
6 x (n – 1) = 894
(n – 1) = 149
n = 150.
[B].
[C].
[D].
Answer: Option D
Explanation:
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0, So, 415624 is divisible by 11.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the given number be 476 xy 0.
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.
And, (0 + x + 7) – (y + 6 + 4) = (x – y -3) must be either 0 or 11.
x – y – 3 = 0 y = x – 3
(17 + x + y) = (17 + x + x – 3) = (2x + 14)
x= 2 or x = 8.
x = 8 and y = 5.
[B].
[C].
[D].
Answer: Option D
Explanation:
24 = 3 x8, where 3 and 8 co-prime.
Clearly, 35718 is not divisible by 8, as 718 is not divisible by 8.
Similarly, 63810 is not divisible by 8 and 537804 is not divisible by 8.
Consider option (D),
Sum of digits = (3 + 1 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 3.
Also, 736 is divisible by 8.
3125736 is divisible by (3 x 8), i.e., 24.
[B].
[C].
[D].
Answer: Option A
Explanation:
6 = 3 x 2. Clearly, 5 * 2 is divisible by 2. Replace * by x.
Then, (5 + x + 2) must be divisible by 3. So, x = 2.
[B].
[C].
[D].
Answer: Option E
Explanation:
Clearly, 4864 is divisible by 4.
So, 9P2 must be divisible by 3. So, (9 + P + 2) must be divisible by 3.
P = 1.
[B].
[C].
[D].
Answer: Option C
Explanation:
Unit digit in 34 = 1 Unit digit in (34)16 = 1
Unit digit in 365 = Unit digit in [ (34)16 x 3 ] = (1 x 3) = 3
Unit digit in 659 = 6
Unit digit in 74 Unit digit in (74)17 is 1.
Unit digit in 771 = Unit digit in [(74)17 x 73] = (1 x 3) = 3
Required digit = Unit digit in (3 x 6 x 3) = 4.
[B].
[C].
[D].
Answer: Option A
Explanation:
80 = 2 x 5 x 8
Since 653xy is divisible by 2 and 5 both, so y = 0.
Now, 653x is divisible by 8, so 13x should be divisible by 8.
This happens when x = 6.
x + y = (6 + 0) = 6.