Center of Gravity and Centroid

Determine the approximate amount of paint needed to cover the surface of the water storage tank. Assume that a liter of paint covers 2.5 m2. Also, what is the total inside volume of the tank.

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Question: Determine the approximate amount of paint needed to cover the surface of the water storage tank. Assume that a liter of paint covers 2.5 m2. Also, what is the total inside volume of the tank.
[A].

27.6 liters of paint, V = 52.6 m3

[B].

20.1 liters of paint, V = 50.3 m3

[C].

26.4 liters of paint, V = 56.5 m3

[D].

25.1 liters of paint, V = 55.0 m3

Answer: Option C

Explanation:

No answer description available for this question.

Determine the distance to the centroid axis of the beam’s cross-sectional area. Neglect the size of the corner welds at A and B for the calculation.

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Question: Determine the distance to the centroid axis of the beam’s cross-sectional area. Neglect the size of the corner welds at A and B for the calculation.
[A].

= 75.2 mm

[B].

= 97.5 mm

[C].

= 85.9 mm

[D].

= 102.5 mm

Answer: Option C

Explanation:

No answer description available for this question.

Locate the center of gravity of the homogeneous “bell-shaped” volume formed by revolving the shaded area about the y axis.

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Question: Locate the center of gravity of the homogeneous “bell-shaped” volume formed by revolving the shaded area about the y axis.
[A].

= 3.33 ft

[B].

= 2.80 ft

[C].

= 3.20 ft

[D].

= 3.00 ft

Answer: Option A

Explanation:

No answer description available for this question.

Locate the center of gravity of the volume generated by revolving the shaded area about the z axis. The material is homogeneous.

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Question: Locate the center of gravity of the volume generated by revolving the shaded area about the z axis. The material is homogeneous.
[A].

= 2.80 ft

[B].

= 2.50 ft

[C].

= 2.67 ft

[D].

= 3.00 ft

Answer: Option C

Explanation:

No answer description available for this question.