Product of two co-prime numbers is 117. Their L.C.M should be__________?
A. 1
B. 117
C. equal to their H.C.F
D. Cannot be calculated
Explanation:
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117.
A. 1
B. 117
C. equal to their H.C.F
D. Cannot be calculated
Explanation:
H.C.F of co-prime numbers is 1.
So, L.C.M = 117/1 = 117.
A. 4
B. 5
C. 6
D. 8
E. None of these
Explanation:
If Bilal gives ‘x’ marbles to Arslan then Bilal and Arslan would have V – x and A + x marbles.
V – x = A + x — (1)
If Arslan gives 2x marbles to Bilal then Arslan and Bilal would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.
A. Rs. 6400
B. Rs. 5600
C. Rs. 5000
D. Rs. 4800
E. None of these
Explanation:
Given SP = Rs. 6800
Marked price = [SP(100)]/(100 – d%) = (6800 * 100)/(100 – 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000
A. 9000
B. 9400
C. 9600
D. 9800
Explanation:
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600
A. 18/35
B. 12/35
C. 17/35
D. 19/35
Explanation:
If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35 = 18/35
A. 33 1/3 %
B. 9 1/11 %
C. 11 1/9 %
D. 66 2/3 %
E. None
A. 30°
B. 45°
C. 60°
D. 90°
Let AB be the tree and AC be its shadow.
Let ∠ACB = θ.
Then, AC/AB = √3
Cot θ = √3
θ = 30°