A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?

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Question:
A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?

[A].

5

[B].

6

[C].

7

[D].

7 1
2

Answer: Option B

Explanation:

Work done = 5
8
Balance work = 1 – 5 = 3
8 8

Let the required number of days be x.

Then, 5 : 3 = :: 10 : x     5 x x = 3 x 10
8 8 8 8
x = 3 x 10 x 8
8 5

x = 6.

A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:

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Question: A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:

[A].

10 m

[B].

12.5 m

[C].

17.5 m

[D].

21.25 m

Answer: Option B

Explanation:

Let the height of the building x metres.

Less lengthy shadow, Less in the height (Direct Proportion)

40.25 : 28.75 :: 17.5 : x       40.25 x x = 28.75 x 17.5

x = 28.75 x 17.5
40.25

x = 12.5

An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?

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Question:
An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?

[A].

178

[B].

195

[C].

204

[D].

488

Answer: Option B

Explanation:

Le the required time be x seconds.

More metres, More time (Direct Proportion)

0.128 : 25 :: 1 : x       0.128x = 25 x 1

x = 25 = 25 x 1000
0.128 128

x = 195.31.

Required time = 195 sec (approximately).

It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

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Question:
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

[A].

Sunday

[B].

Saturday

[C].

Friday

[D].

Wednesday

Answer: Option C

Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

The last day of a century cannot be

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Question:
The last day of a century cannot be

[A].

Monday

[B].

Wednesday

[C].

Tuesday

[D].

Friday

Answer: Option C

Explanation:

100 years contain 5 odd days.

Last day of 1st century is Friday.

200 years contain (5 x 2) 3 odd days.

Last day of 2nd century is Wednesday.

300 years contain (5 x 3) = 15 1 odd day.

Last day of 3rd century is Monday.

400 years contain 0 odd day.

Last day of 4th century is Sunday.

This cycle is repeated.

Last day of a century cannot be Tuesday or Thursday or Saturday.