Mapping the SOP expression , we get ________.
Question: Mapping the SOP expression , we get ________.
[A].
(A)
(B)
(C)
(D)
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
No answer description available for this question.
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A NAND gate is called a universal logic element because______________?
A NAND gate is called a universal logic element because______________?A. it is used by everybody
B. any logic function can be realized by NAND gates alone
C. all the minization techniques are applicable for optimum NAND gate realization
D. many digital computers use NAND gatesWhich mechanism allocates the binary value to the states in order to reduce the cost of the combinational circuits ?
Which mechanism allocates the binary value to the states in order to reduce the cost of the combinational circuits ?A. State Reduction
B. State Minimization
C. State Assignment
D. State EvaluationA + AB =
Question: A + AB =
[A].A [B].
A [C].
A + B [D].
A + B Answer: Option C
Explanation:
No answer description available for this question.
What is the octal equivalent of the binary number : 10111101 ?
What is the octal equivalent of the binary number : 10111101 ?A. 675
B. 275
C. 572
D. 573A seven bit code (even parity) 1111101 may have error. The correct code is
Question: A seven bit code (even parity) 1111101 may have error. The correct code is
[A].1111101 [B].
1111111 [C].
0101011 [D].
1100011 Answer: Option B
Explanation:
No answer description available for this question.
A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH
Question: A NOR gate has 3 inputs A, B, C. For which combination of inputs is output HIGH
[A].A = B = C = 0 [B].
A = B = C = 1 [C].
A = B = 1 and C = 0 [D].
A = C = 1 and B = 0 Answer: Option A
Explanation:
NOR gate gives High output when all inputs are Low.