In order to obtain an income of Rs. 650 from 10% stock at Rs. ,96, one must make an investment of___________?
A. Rs. 3100
B. Rs. 6240
C. Rs. 6500
D. Rs. 9600
A. Rs. 3100
B. Rs. 6240
C. Rs. 6500
D. Rs. 9600
A. No loss or gain
B. Loss of Rs. 1000
C. Gain of Rs. 1000
D. Gain of Rs. 2000
Explanation:
Loss% = (20/10)2 = (2)2 = 4%
Total S.P = Rs. 24000
Total C.P = Rs. (100/96 × 24000) = Rs. 25000
Loss = Rs. 1000
A. Rs.900
B. Rs.875
C. Rs.850
D. Rs.860
Explanation:
CP = SP + 1CP = SP – g
800 + x = 980 – 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
A. Rs.18000
B. Rs.13000
C. Rs.15000
D. Rs.10000
4S+5D+3C=130000 3C=2D 3D=2S S=3D/2 [4*(3D/2)]+5D+2D = 130000 6D+5D+2D = 130000 13D = 130000 D = Rs.10000 S=3D/2 = Rs.15000
A. Rs.3
B. Rs.4.50
C. Rs.5.00
D. Rs.7.50
2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
A. 4
B. 6
C. 3
D. 2
Let the numbers be 2x and 3x. (2x)³+(3x)³=280 8x³+27x³=280 35x³=280 x³=8 x=2 The numbers are 4 and 6.
A. 4 days
B. 6 days
C. 2 days
D. 8 days
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 — (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = ½
=> 52m + 96b = 1— (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days