A. 15%
B. 65%
C. 60%
D. 70%
A. 3 hours 20 minutes
B. 3 hours 15 minutes
C. 3 hours 30 minutes
D. 3 hours
Let his usual speed be x kmph, the distance to his office be y km and his usual travel time be t hrs. y = xt = (5/6)x * (t+(40/60)) Solving the equation,
t = 3.33 hrs = 3 hrs 20 minutes
A. 39:40
B. 40:39
C. 3:4
D. 4:3
Explanation:
3: 4
A = 3/7*210 = 90
390: 400
39:40
As we know about BODMAS rule i.e brackets of division multiplication addition subtraction.
{ 2 +[ (2/2) *2] } -2
{ 2 +[ 1*2] } -2
{ 2 +[ 2] } -2
{ 4 } -2. So answer is 2.
A. 4000
B. 3050
C. 4400
D. 4500
E. None of these
Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000.
A. Rs.350
B. Rs.375
C. Rs. 380
D. Rs. 400
Explanation:
The principle is P.
P(1 +10/100)2 – P = 420
=> P = Rs.2000
S.I = Rs.(4000/100) = Rs.400
A. Rs 230
B. Rs 232
C. Rs 600
D. Rs 832
Explanation:
S.I = Rs (6000 × 5/100 × 2) = Rs 600
C.I = Rs [5000 × (1 + 8/100)2 – 5000]
= Rs (5000 × 27/25 × 27/25 – 5000)
= Rs(5832 – 5000)
= Rs 832
(C.I) – (S.I) = Rs (832 – 600) = Rs 232