In a fort the food was sufficient for two months. After half a month
		A. 1.5 months
B. 40 days
C. 2 months
D. 50 days
		A. 1.5 months
B. 40 days
C. 2 months
D. 50 days
		A. 3 * 2.75 * 2.75 * 2.75
B. 3 * 2.00 * 2.00 * 2.00
C. 3 * 2.75 * 0.75 * 2.75
D. 4.5 * 2.75
Explanation:
(2.75)3 – (2.00)3 – (0.75)3
a3 + b3 + c3 = (a + b + c)(a3 + b3 + c3 – ab – bc – ca)
If a + b + c = 0 then a3 + b3 + c3 = 3abc
Hence 2.75 – 2.00 – 0.75 = 0
So, (2.75)3 – (2.00)3 – (0.75)3
= 3 * 2.75 * 2 * 0.75 = 3 * 1.5 * 2.75
= 4.5 * 2.75
		A. 2:3
B. 3:2
C. 3:4
D. 4:3
x+y = 750 y-x = 150 Solving,
y = 450
x = 300 x:y = 300:450 = 2:3
		A. 10%
B. 15%
C. 20%
D. 25%
Explanation:
Let C.P of each mango = Rs. 1
C.P of 320 mangoes = Rs. 320
S.P of 320 mangoes = Rs. 400
Gain = (80/320 × 100)% = 25 %
		A. Rs. 10
B. Rs. 10.40
C. Rs. 15.20
D. Rs. 13
		A. 36
B. 81
C. 91
D. 116
Explanation:
When the dice are rolled, the number of possible outcomes = 63 = 216.
Number of possible outcomes in which 2 does not appear on any dice = 53 = 125.
Therefore, Number of possible outcomes in which at least one dice shows 2 = 216- 125 = 91.
		A. 20
B. 30
C. 60
D. None of these
Explanation:
Area of the plot = (3×1200)Sq.m = 3600 Sq.m
Breadth = x meters and length = 4x meters
4x × x = 3600 or x2 = 900 0r x = 30
Length of plot = 4x = (4×30) m = 120 m