In 50 gm alloy of gold and silver the gold is 80 % by weight. How much gold should be mixed with this alloy so that the weight of gold would become 95 %?
A. 200 gm
B. 150 gm
C. 50 gm
D. 10 gm
A. 200 gm
B. 150 gm
C. 50 gm
D. 10 gm
A. 1500
B. 1750
C. 9000
D. 7500
Explanation:
9000 + 16 2/3 % of ? = 10500 => 9000 + 50/3 % of ? = 10500
50/(3 * 100) of ? = 1500 => ? = 1500 * 6
? = 9000
A. 225 cm2
B. 275 cm2
C. 285 cm2
D. 315 cm2
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2
A. 22. 5 %
B. 27.5 %
C. 32. 5 %
D. 37.5 %
Explanation:
Males = (60/100 × 1000) = 600,
females = (1000 – 600) = 400
Literate males = (20/100 × 600) = 120
Total literates = (25/100 × 1000) = 250
Female literates = (250 – 120) = 130
Required % = (130/400 × 100)% = 32.5 %
A. 34
B. 17
C. 85
D. 204
A. 2700
B. 2900
C. 3000
D. 3100
Explanation:
Valid votes = (80/100 × 7500) = 6000
Valid votes polled by one candidates
=(55/100 × 6000) = 3300
Valid votes polled by another candidate
= (6000 – 3300) = 2700
A. Rs.400
B. Rs.500
C. Rs.300
D. Rs.600
E. None of these
Explanation:
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500.