A. 16%
B. 16 1/3 %
C. 20%
D. 16 3/5 %
X=100 y=125
125——–25
100——–? => 20%
A. 4334.04
B. 4243.04
C. 4343.04
D. 4433.04
Explanation:
? = 4343.04
A. 8 cm
B. 12 cm
C. 14 cm
D. 10 cm
A. 37
B. 38
C. 39
D. 40
Explanation:
Perimeter = 2×(36+21) m = 114 m
Number of flag staffs = (114/3) = 38
A. 27 m
B. 24 m
C. 18 m
D. 21 m
Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
As we know about BODMAS rule i.e brackets of division multiplication addition subtraction.
{ 2 +[ (2/2) *2] } -2
{ 2 +[ 1*2] } -2
{ 2 +[ 2] } -2
{ 4 } -2. So answer is 2.
A. 4000
B. 2160
C. 4320
D. 5300
Explanation:
x Not younger_______ ↑
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320