If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:
		A. Rs. 20
B. Rs. 21.81
C. Rs. 22
D. Rs. 18.33
		A. Rs. 20
B. Rs. 21.81
C. Rs. 22
D. Rs. 18.33
		A. 36km/h
B. 45km/h
C. 48km/h
D. 50km/h
Explanation:
Speed of person from x to y =40 km/h
Speed of person from y to x =(40×150)/100 = 60km/h
Since the distance travelled is same
Therefore, Average Speed = (2x40x60)/40+60 = 48km/h
		A. 20
B. 40
C. 60
D. 80
Explanation:
32/100 * 425 – x/100 * 250 = 36
 => x/100 * 250 = 136 – 36 = 100
=> x = (100 * 100)/250 = 40
		A. 133.33 kmph
B. 1.33 kmph
C. 4 kmph
D. 8 kmph
He crosses 0.4 km in 3/60th of an hour. Speed = 0.4/(1/20) = 8 kmph
		A. 3800
B. 4200
C. 4400
D. 5500
Explanation:
X * (95/100) * (85/100) = 3553
X = 4400
		A. 8
B. 6
C. 4
D. 2
Explanation:
Let n erasers be available for a rupee
Reduced Price = (75/100 × 1) = Re ¾
 ¾ rupee fetch n erasers = 1 Rupee will fetch (n × 4/3) erasers
Therefore, 4n/3 = n +2 => 4n = 3n +6 => n =6
		A. 70%
B. 37%
C. 53%
D. 30%