If n is a natural number, then (6n2 + 6n) is always divisible by:

Question:
If n is a natural number, then (6n2 + 6n) is always divisible by:

[A].

6 only

[B].

6 and 12 both

[C].

12 only

[D].

by 18 only

Answer: Option B

Explanation:

(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.