If logxy = 100 and log2x = 10, then the value of y is:
If logxy = 100 and log2x = 10, then the value of y is:
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
log 2x = 10 x = 210.
logxy = 100
y = x100
y = (210)100 [put value of x]
y = 21000.
[B].
[C].
[D].
Answer: Option C
Explanation:
log 2x = 10 x = 210.
logxy = 100
y = x100
y = (210)100 [put value of x]
y = 21000.
| 7 |
| 8 |
[B].
| 13 |
| 16 |
[C].
| 31 |
| 40 |
[D].
| 63 |
| 80 |
Answer: Option A
Explanation:
L.C.M. of 8, 16, 40 and 80 = 80.
| 7 | = | 70 | ; | 13 | = | 65 | ; | 31 | = | 62 |
| 8 | 80 | 16 | 80 | 40 | 80 |
| Since, | 70 | > | 65 | > | 63 | > | 62 | , so | 7 | > | 13 | > | 63 | > | 31 |
| 80 | 80 | 80 | 80 | 8 | 16 | 80 | 40 |
| So, | 7 | is the largest. |
| 8 |
[B].
[C].
[D].
Answer: Option C
Explanation:
Clearly, the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
[B].
[C].
[D].
Answer: Option D
Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
14 : 6 :: 21 : x 14 x x = 6 x 21
| x = | 6 x 21 |
| 14 |
x = 9.
[B].
[C].
[D].
Answer: Option C
Explanation:
Then number 6×2 must be divisible by 8.
x = 3, as 632 is divisible 8.
[B].
[C].
[D].
Answer: Option D
Explanation:
(4 + 5 + 2) – (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) – (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) – (2 + 5 + 4) = 0, So, 415624 is divisible by 11.