If in a box of dimensions 6 m * 5 m * 4 m smaller boxes of dimensions 60 cm * 50 cm * 40 cm are kept in it, then what will be the maximum number of the small boxes that can be kept in it?
A. 500
B. 1000
C. 900
D. 600
A. 500
B. 1000
C. 900
D. 600
A. (400 – 100π) cm2</sup
B. (400 – 2π) cm2</sup
C. (400 – 200π) cm2</sup
D. 200π cm2</sup
A. 150
B. 200
C. 225
D. 300
Explanation:
75 + 75 % of x = x
or x – 3/4 x = 75
Or 1/4 x = 75
X = (75 × 4) =300
A. 14
B. 16
C. 18
D. 20
E. None of these
Explanation:
Let the present ages of Aftab and Kashif be ‘a’ and ‘b’ respectively.
a – 10 = 1/3 (b – 10) — (1)
b = a + 12
Substituting b = a + 12 in first equation,
a – 10 = 1/3 (a + 2) => 3a – 30 = a + 2
=> 2a = 32 => a = 16.
A. 1/216
B. 1/36
C. 5/9
D. 5/12
Explanation:
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
A. 1994
B. 1494
C. 1349
D. 1496
LCM = 1400
1400 – 6 = 1394
A. Rs 1575.20
B. Rs 1600
C. Rs 1625.80
D. Rs 2000
Explanation:
Amount = Rs[10000 × (1 + 4/100) × (1 +5/100) × (1 × 6/100)]
= Rs(1000 × 26/25 × 21/20 × 53/50)
= Rs (57876/5) = Rs 11575.20
C.I = Rs (11575.20 – 10000) = Rs 1575.20