A. 2 years
B. 3 years
C. 1 year
D. 4 years
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T=100×SI/PR =100*81/900*4.5 =2 years
A. 16 2/3% loss
B. 100/3% loss
C. 50/3% profit
D. 100/3% loss
Explanation:
15 CP = 18 SP
18 — 3 CP loss
100 — ? => 16 2/3% loss
A. 3
B. 4
C. 5
D. 6
Explanation:
P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years.
A. 16 hours
B. 15 hours
C. 18 hours
D. 17 hours
Explanation:
Let the leak can empty the full tank in x hours 1/6 – 1/x = 1/9
=> 1/x = 1/6 – 1/9 = (3 – 2)/18 = 1/18
=> x = 18.
A. 2km/hr
B. 2.8 km/hr
C. 4 km/hr
D. 4.2 km/hr
E. None of these
Explanation:
Speed downstream = 24/10 km/hr = 2.4 km/hr
Speed upstream = 24/12 km/hr = 2 km/hr
Speed of the boat in still water = ½ (2.4 +2)km/hr = 2.2 km/hr
A. 4 days
B. 6 days
C. 2 days
D. 8 days
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 — (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = ½
=> 52m + 96b = 1— (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
A. 2:3:5
B. 8:12:15
C. 2:8:5
D. 2:7:5
If A:B = m1:n1 ; B:C = m2:n2
Then, A:B:C = (m1*m2):(n1*m2):(n1*n2)
Therefore, X:Y:Z = (2*4):(3*4):(3*5)
= 8:12:15