he perimeter of a circle and a square field are equal. What is the diameter of the circle field if the area of the square field is 484 sq.m?
		A. 14m
B. 21m
C. 28m
D. None of these
		A. 14m
B. 21m
C. 28m
D. None of these
		A. Rs. 110
B. Rs. 120
C. Rs. 140
D. None of these
Explanation:
Let the cost of the brand be Rs. X per kg.
C.P. of 5 kg = (2 * 200 + 3 * x) = Rs. (400 + 3x)
S.P of 5 kg = Rs. (5 * 177) = Rs. 885
[885 – (400 + 3x)]/(400 + 3x) * 100 = 18
24250 – 150x = 3600 + 27x
177x = 20650 => x = 116 2/3
So, cost of the other brand = Rs. 116.66.
		A. 3
B. 4
C. 5
D. 6
		A. 4000
B. 3050
C. 4400
D. 4500
E. None of these
Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000.
		A. 7203
B. 2403
C. 3603
D. 4803
		A. 120
B. 260
C. 240
D. 220
Explanation with best method.
5 Steps
1.Data:
Train station platform= 36Sec
Standing platform = 20Sec
Speed of train = 54km/hr
2.Required:
Length of platform= x=???
3.Formula:
X+length of train/Train station platform
4.Solution: first for terms
Speed = 54 ×1000m/3600sec = 15 m/Sec.
Length of the train = (15 m/Sec × 20Sec = 300 m.
Let the length of the platform be x metres.
Now, x + 300m /36Sec= 15 m/Sec
x+300m= 15m/Sec×36Sec
x + 300m = 540m
x= 540m-300m
x = 240 m.
5.Result:
Length of platform=x=240m
		A. 15%
B. 16 1/6%
C. 16 2/3%
D. 20%
Explanation:
Clearly, the retailer gets 1 dozen out of 6 dozens free.
Equivalent discount = 1/6 * 100 = 16 2/3%.