Our website is made possible by displaying online advertisements to our visitors. Please consider supporting us by whitelisting our website.

From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

/ Aptitude, Height And Distance / By
Question: From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
[A].

149 m

[B].

156 m

[C].

173 m

[D].

200 m

Answer: Option C

Explanation:

Let AB be the tower.

Then, APB = 30° and AB = 100 m.

AB = tan 30° = 1
AP 3
AP = (AB x 3) m
= 1003 m
= (100 x 1.73) m
= 173 m.