A. 3:4
B. 4:3
C. 3:1
D. 1:3
4 πr2 : 3 πr2 => 4:3
A. ¹²C₅ * 10
B. ¹²C₇ * 10
C. ¹²C₇ * ¹⁰C₅
D. 12 * ¹⁰C₅
Here, five seniors out of 12 seniors can be selected in ¹²C₅ ways. Also, five juniors out of ten juniors can be selected ¹⁰C₅ ways. Hence the total number of different ways of selection = ¹²C₅ * ¹⁰C₅ = ¹²C₇ * ¹⁰C₅
= ¹²C₅ = ¹²C₇
A. 11
B. 24
C. 45
D. cannot be determined
Let the total number of children be x.
Then x × 20/100 × x = 605
=> x2 = 3025
=> x = √3025 = 55
Number of sweets received by each child
= (20/100 ×55) = 11
A. 9985
B. 9960
C. 9957
D. 9975
Explanation:
Greatest 4-digit number is 9999. LCM of 3, 4 and 5 is 60. Dividing 9999 with 60, we get remainder 39. Thus, the required number is 9999 – 39 = 9960.
A. 5km/hr
B. 8 km/hr
C. 10 km/hr
D. 15 km/hr
A. 1300 m3
B. 1331 m3
C. 1452 m3
D. 1542 m3
6a2 = 726
=> a2 = 121
=> a = 11 Cm
Therefore, Volume of the cube
= (11 × 11 × 11) cm3 = 1331 cm3
A. 10%
B. 12%
C. 6%
D. 8%
Explanation:
5000 = 72(100/R)2
5 R2 = 720 => R = 12