Find the least number which when divided by 6, 7, 8, 9 and 10 leaves 1, 2, 3, 4 and 5 as remainders respectively, but when divided by 19 leaves no remainder?
A. 5073
B. 5016
C. 5054
D. 5035
A. 5073
B. 5016
C. 5054
D. 5035
A. Rs.4000
B. Rs.9000
C. Rs.5000
D. Rs.6000
Let sum = P and original rate = R. Then
[(P * (R+2) * 3)/100] – [ (P * R * 3)/100] = 360
3P*(R+2) – 3PR = 36000
3PR + 6P – 3PR = 36000
6P = 36000
P = 6000
A. 120
B. 240
C. 360
D. 480
Explanation:
1. As there are six players, So total ways in which they can be arranged = 6!ways =720.
A number of ways in which Asim and Raheem are together = 5!x2 = 240.
Therefore, Number of ways when they don’t remain together = 720 -240 =480.
A. Rs. 8082
B. Rs. 7800
C. Rs. 8100
D. Rs. 8112
Explanation:
Amount = Rs. [7500 (1 +4/100)2]
= Rs. [7500 × 26/25 × 26/25] = Rs.8112
A. 123
B. 137
C. 121
D. 122
Sum of 18 observations = 18×124 =2232
Correct sum of 18 observations = 2232-46-82+64+28
= 2196
Therefore, Correct average =2196/18 = 122
A. 100
B. 121
C. 64
D. 144
LCM = 72
72 * 2 = 144