Find the H.C.F of 204, 1190 and 1445?
A. 34
B. 17
C. 85
D. 204
A. 34
B. 17
C. 85
D. 204
A. 3: 5
B. 2: 5
C. 3: 1
D. 1: 3
A. 1/3 rd
B. 2/5 th
C. 2/3 rd
D. 1/5 th
Explanation:
3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
A. 0.60 minutes
B. 0.36 minutes
C. 0.78 minutes
D. 0.42 minutes
Total distance = addition of length of the two trains = 140 + 120 = 260 metres
As the two trains are travelling in the same direction, their relative speed is:
v = | v1 – v2 | = | 40 – 60 | = 20 km/hr = 20*1000/60 = 1000/3 metres/min
t = 260/ 1000*3
t = 0.78 minutes
A. 12 liters
B. 10 liters
C. 4 liters
D. 2 liters
Explanation:
70 * (10/100) = 7
Wine Water
87 1/2% 12 1/2%
87 1/2% ——- 63
12 1/2% ——-? => 9-7=2
A. 5/21
B. 5/14
C. 9/14
D. 16/21
Explanation:
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21