Find the H.C.F of 12, 16, 18 and 24?
Find the H.C.F of 12, 16, 18 and 24?
A. 1
B. 2
C. 3
D. 4
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The temperature at noon in LHR ,Pakistan was 6 deg on Monday ,4deg on Tuesday,2deg below zero on Wednesday,3deg below zero on Thursday, 0 deg on Friday ,3 deg on Saturday ,and 6 deg on Sunday. What was the average temperature at noon for the week ?
The temperature at noon in LHR ,Pakistan was 6 deg on Monday ,4deg on Tuesday,2deg below zero on Wednesday,3deg below zero on Thursday, 0 deg on Friday ,3 deg on Saturday ,and 6 deg on Sunday. What was the average temperature at noon for the week ?A. 14 deg
B. -2 deg
C. 2 deg
D. 7 deg105 * 99 * 299 = _________?
105 * 99 * 299 = _________?A. 785600
B. 315000
C. 845000
D. 442000Explanation:
105 * 99 * 299 = 105 * 100 * 300 = 315000The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?
The ratio between the sale price and the cost price of an article is 7:5. What is the ratio between the profit and the cost price of that article?A. 2:7
B. 5:2
C. 7:2
D. Data inadequate
E. None of these
Explanation:
Let C.P. = Rs. 5x and S.P. = Rs. 7x.
Then, Gain = Rs. 2x
Required ratio = 2x : 5x = 2:5What part of a ditch 48m long 16.5 broad and 4m deep can be filled by the earth got by digging a cylindrical tunnel of diameter 4m and length 56m?
What part of a ditch 48m long 16.5 broad and 4m deep can be filled by the earth got by digging a cylindrical tunnel of diameter 4m and length 56m?A. 1/9
B. 2/9
C. 7/9
D. 8/9The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________?
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________?A. 123
B. 127
C. 235
D. 305
Explanation:
Required number = H.C.F. of (1657 – 6) and (2037 – 5)= H.C.F. of 1651 and 2032 = 127.A and B are two fixed points 5 cm apart and c is a point on AB such that AC = 3 cm. If the length of AC is increased by 6 % the length of CB is decreased by:_________?
A and B are two fixed points 5 cm apart and c is a point on AB such that AC = 3 cm. If the length of AC is increased by 6 % the length of CB is decreased by:_________?A. 6 %
B. 7 %
C. 8 %
D. 9 %
Explanation:
AC = 3cm, CB = (5 – 3)cm = 2 cm
New length AC = 106 % of 3 cm
= (106/100 ×3) cm = 3.18 cm.
New length CB = (5 – 3.18) cm = 1.82 cm
CB Decreased on 2cm = (2 – 1.82)cm = 0.18cm
CB Decrease % = (0.18/2 ×100) % = 9 %