Find the greatest number of four digits which when divided by 10, 15, 21 and 28 leaves 4, 9, 15 and 22 as remainders respectively?
		A. 9654
B. 9666
C. 9664
D. 9864
		A. 9654
B. 9666
C. 9664
D. 9864
		A. Rs. 80
B. Rs. 85
C. Rs. 90
D. Rs. 95
E. None of these
Explanation:
SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth – profit on 1m of cloth
= Rs. 105 – Rs. 15 = Rs. 90.
		A. 16
B. 12
C. 8
D. 6
Let the number of women workers be x
According to the question 22*x+16*8 = 15(16+x)
=> 22x+128 =240 +15x
=> 22x-15x = 240 -128
=> 7x=112
Therefore, x=112/7 =16
Therefore, Unmarried women workers =(16-10) = 6
		A. 4/9
B. 2/3
C. 4/7
D. 1/6
Explanation:
2/3 —- 12
? —– 8 ==> 4/9
		A. 45
B. 50
C. 51.4 approx.
D. 54.6 approx.
Explanation:
Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4.
		A. loss of Rs. 200
B. loss of Rs. 100
C. profit of Rs. 100
D. profit of Rs. 200
E. None of these
Explanation:
Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 – 4/100) = 15000 – 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP – Total CP = r + m – (15000 + 8000) = -600 + 800 = Rs. 200
As this is positive, an overall profit of Rs. 200 was made.
		A. 4%
B. 5%
C. 6%
D. 8%
Explanation:
SI = 20 + 20
CI = 20 + 21
20 —- 1
100 —- ? => 5%