Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
		A. 120 sq m
B. 150 sq m
C. 110 sq m
D. 300 sq m
		A. 120 sq m
B. 150 sq m
C. 110 sq m
D. 300 sq m
		A. 2 hrs 15 min
B. 4 hrs 24 min
C. 5 hrs
D. 3 hrs
Explanation:
1/4 + 1/5 = 9/20
 20/9 = 2 2/9
 9/20 * 2 = 9/10 —- 4 hours
 WR = 1 – 9/10 = 1/10
 1 h —- 1/4
 ? —– 1/10
 2/5 * 60 = 24 = 4 hrs 24 min
		A. 56
B. 42
C. 38
D. 34
Explanation:
HCF of 374, 544 = 34
		A. 52.65
B. 56.25
C. 50.75
D. 42.75
		A. Has increase by 20%
B. Has increase by 12%
C. Has increase b 8%
D. Is exactly the same as the old area
		A. 6
B. 9
C. 24
D. 30
Volume of block = (6 X 9 X 12) cm3 = 648 cm3.
Side of largest cube = H.C.F. of 6 cm, 9 cm, 12 cm = 3 cm.
Volume of this cube = (3 X 3 X 3) = 27 cm3.
Number of cubes = 648/27 = 24.
		A. 295m2
B. 299m2
C. 300m2
D. 375m2
Explanation:
Area under the grass = [(25 x 15) – {(25 x 2)+ (15 x 2) – (2 x 2)}] Sq.m
= [375 –(50 +30 -4)]Sq.m =(375 – 76)Sq.m = 299 Sq.m