Compound Interest | Mathematics Mcqs

Find the amount on Rs.5000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?

Byadmin September 23, 2019July 26, 2021

Find the amount on Rs.5000 in 2 years, the rate of interest being 4% per first year and 5% for the second year?

A. Rs.460
B. Rs.5640
C. Rs.5460
D. Rs.5604

Mathematics Mcqs | Simplification and Approximation

(180/37 of 14.8) / (17/60.1 of 180.30) = _______?

(180/37 of 14.8) / (17/60.1 of 180.30) = _______?

A. 1.4
B. 1.6
C. 1.5
D. 1.2
Explanation:
(180/37 of 14.8) / (17/60.1 of 180.30) = 72/51 = 24/17 = 1.41

Read More (180/37 of 14.8) / (17/60.1 of 180.30) = _______?
Basic Maths Mcqs | Boats and Streams | Mathematics Mcqs

The speed of a motor boat is that of the current of water as 36:5. The boat goes along with the current in 5 hours 10 min, it will come back in_______?

The speed of a motor boat is that of the current of water as 36:5. The boat goes along with the current in 5 hours 10 min, it will come back in_______?

A. 5 hours 50 min
B. 6 hours
C. 6 hours 50 min
D. 12 hours 10 min
Explanation:
Let the speed of motor boat be 36x km/hr and that of current of water be 5x km/hr
Speed downstream = (36x +5x)km/hr = 41x km/hr
Speed upstream = (36 -5x)km/hr = 31x km/hr
Distance covered downstream = (41x × 31/6)km
Distance upstream = [1271x/6 × 1/31x]hrs
= 41/6 hrs = 6hrs 50 min

Read More The speed of a motor boat is that of the current of water as 36:5. The boat goes along with the current in 5 hours 10 min, it will come back in_______?
Mathematics Mcqs | Simplification and Approximation

(815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680

(815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680

A. 2000
B. 3000
C. 4000
D. 6000
Explanation:
Let 815 + ? be k
=> 84k/100 – (815 * 84)/100 = 1680
=>84(k/100 – 815/100) = 1680
=> (k – 815)/100 = 20 => k = 2815
k = 815 + ? = 2815 => ? = 2000

Read More (815 / ?) / 100 * 28 * 3 – (815 * 14 * 6)/100 = 1680
Mathematics Mcqs | Mixtures and Allegations

How much water must be added to a bucket which contains 40 liters of milk at the cost price of Rs.3.50 per liter so that the cost of milk reduces to Rs.2 per liter?

How much water must be added to a bucket which contains 40 liters of milk at the cost price of Rs.3.50 per liter so that the cost of milk reduces to Rs.2 per liter?

A. 25 liters
B. 28 litres
C. 30 liters
D. 35 liters
Explanation:
Total cost price =Rs(40 x 7/2) = Rs.140
Cost per litre =Rs.2,
Total quantity = 140/2 = 70 Litres.
Water to be added =(70-40) =30 Litres.

Read More How much water must be added to a bucket which contains 40 liters of milk at the cost price of Rs.3.50 per liter so that the cost of milk reduces to Rs.2 per liter?
Mathematics Mcqs | Percentage Mcqs

10 % of the electorate did not cast their votes in an election between two candidates. 10 % of the votes polled were found invalid. The successful candidate got 54 % of the valid votes and won by a majority of 1620 votes. The number of voters enrolled on the voter’s list was___________?

10 % of the electorate did not cast their votes in an election between two candidates. 10 % of the votes polled were found invalid. The successful candidate got 54 % of the valid votes and won by a majority of 1620 votes. The number of voters enrolled on the voter’s list was___________?

A. 25000
B. 33000
C. 35000
D. 40000
Explanation:
Let the number of votes enrolled be x
Votes cast = (90/100 × x) = 9x/10
Valid votes = 90% of 9x/10 = (90/100 × 9x/10) = 81x/100
Votes polled by successful candidate
= (54/100 × 81x/100) = 4374x/10000
Votes polled by defeated candidate
= (46/100 × 81x/100) = 3726x/10000
=> 4374x – 3726x = 16200000
=> x = 16200000/648 = 25000

Read More 10 % of the electorate did not cast their votes in an election between two candidates. 10 % of the votes polled were found invalid. The successful candidate got 54 % of the valid votes and won by a majority of 1620 votes. The number of voters enrolled on the voter’s list was___________?
Mathematics Mcqs | Volumes

Surface area of a sphere is 2464 cm2. If its radius is doubled, then the surface area of _________?the new sphere will be

Surface area of a sphere is 2464 cm2. If its radius is doubled, then the surface area of _________?the new sphere will be

A. 4920 cm2
B. 4727 cm2
C. 9856 cm2
D. 19712 cm2

Read More Surface area of a sphere is 2464 cm2. If its radius is doubled, then the surface area of _________?the new sphere will be