Question:
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
[A].2 times
3 times
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
[A].
[B].
| 2 | 1 | times |
| 2 |
[C].
| 2 | 3 | times |
| 4 |
[D].
Answer: Option A
Explanation:
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
| (4x + 8) = | 5 | (x + 8) | |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |