complete the series: 4.8.9.13.14.18._______?
A. 22
B. 32
C. 11
D. 19
A. 22
B. 32
C. 11
D. 19
A. 1
B. 2
C. 3
D. 4
Work done by Q in 1 day = 1/12
Work done by P in 1 day = 2 × (1/12) = 1/6
Work done by P and Q in 1 day = 1/12 + 1/6 = ¼
=> P and Q can finish the work in 4 days
A. 855 1/2 grams
B. 833 1/3 grams
C. 833 1/2 grams
D. 875 2/7 grams
Explanation:
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm —— 100 gm
1000 gm —— ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
A. 3.34
B. 2
C. 4.5
D. 5.5
Area of the path = Area of the outer circle – Area of the inner circle = ∏{4/2 + 25/100}2 – ∏[4/2]2
= ∏[2.252 – 22] = ∏(0.25)(4.25) { (a2 – b2 = (a – b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m
A. 14m
B. 18m
C. 4m
D. None of these
Explanation:
Let the breadth be x metres , then it’s length = 3x metres
=>3x × x =12
=> x2= 4
=> x =2 l=6m, b =2m
=> Perimeter = 2(6+2)m = 16m
A. 5 : 3 : 1
B. 5 : 3 : 2
C. 10 : 7 : 4
D. 10 : 8 : 5
E. None of these
Explanation:
Let the prices of X, Y and Z be 8k, 5k and 3k respectively.
After increase
Price of X = 8k * 125/100 = 10k
Price of Y = 5k * 120/100 = 6k
Price of Z = 3k * (133 1/3)/100 = 4k
Required ratio = 10k : 6k : 4k = 5 : 3 : 2.
A. 3180
B. 3200
C. 3120
D. 3210
Explanation:
√3600 * 52 = ?
=> ? = 60 * 52 = 3120