A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?

Question: A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
[A].

4 p.m.

[B].

5 p.m.

[C].

6 p.m.

[D].

None of these

Answer: Option C

Explanation:

Net ascent of the monkey in 1 hour = (30 – 20) feet = 10 feet.

So, the monkey ascends 90 feet in 9 hours i.e. till 5 p.m.

Clearly, in the next 1 hour i.e. till 6 p.m. the monkey ascends remaining 30 feet to touch the flag.

An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?

Question: An institute organised a fete and 1/5 of the girls and 1/8 of the boys participated in the same. What fraction of the total number of students took part in the fete ?
[A].

2/13

[B].

13/40

[C].

Data inadequate

[D].

None of these

Answer: Option C

Explanation:

No answer description available for this question.

An enterprising businessman earns an income of Re. 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. One the 10th day of business, his income is

Question: An enterprising businessman earns an income of Re. 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. One the 10th day of business, his income is
[A].

Rs. 29

[B].

Rs. 210

[C].

Rs. 10

[D].

Rs. 102

Answer: Option A

Explanation:

Income on the first day = Re. 1.

Income on the 2nd day = Rs. (1×2) = Rs. 21.

Income on the 3rd day = Rs. (21 x 2) = Rs. 22 and so on. Thus, Income on the rath day = Rs. 2n-1.

Therefore Income on the 10th day = Rs. 29.

A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ?

Question: A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ?
[A].

100

[B].

104

[C].

108

[D].

None of these

Answer: Option B

Explanation:

Since each pole at the corner of the plot is common to its two sides, so we have :

Total number of poles needed = 27 x 4 – 4 = 108 – 4 = 104.

In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is

Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
[A].

20 m

[B].

22 m

[C].

24 m

[D].

26 m

Answer: Option C

Explanation:

Each row contains 12 plants.

There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.

Therefore Length = (22 + 2) m = 24 m.

A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?

Question: A printer numbers the pages of a book starting with 1 and uses 3189 digits in all. How many pages does the book have ?
[A].

1000

[B].

1074

[C].

1075

[D].

1080

Answer: Option B

Explanation:

No. of digits in 1-digit page nos. = 1×9 = 9.

No. of digits in 2-digit page nos. = 2 x 90 = 180.

No. of digits in 3-digit page nos. = 3 x 900 = 2700.

No. of digits in 4-digit page nos. = 3189 – (9 + 180 + 2700) = 3189 – 2889 = 300.

Therefore No. of pages with 4-digit page nos. = (300/4) = 75.

Hence, total number of pages = (999 + 75) = 1074.