[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the father’s age be x and the son’s age be y.
Then, x – y = y or x = 2y,
Now, x = 36. So, 2y = 36 or y = 18.
Therefore Son’s present age = 18 years.
So, son’s age 5 years ago = 13 years.
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the father’s age be x and the son’s age be y.
Then, x – y = y or x = 2y,
Now, x = 36. So, 2y = 36 or y = 18.
Therefore Son’s present age = 18 years.
So, son’s age 5 years ago = 13 years.
[B].
[C].
[D].
Answer: Option B
Explanation:
We have : A = 3B …(i) and
C – 4 = 2 (A – 4) …(ii)
Also, A + 4 = 31 or A= 31-4 = 27.
Putting A = 27 in (i), we get: B = 9.
Putting A = 27 in (ii), we get C = 50.
[B].
[C].
[D].
Answer: Option B
Explanation:
Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.
Such numbers are 25 and 27.
Thus, Nitin is now 26 years old. Since the next perfect cube after 27 is 64,
so required time period = (64 – 26) years = 38 years.
[B].
[C].
[D].
Answer: Option A
Explanation:
Ayush’s present age = 10 years.
His mother’s present age = (10 + 20) years = 30 years.
Ayush’s father’s present age = (30 + 5) years = 35 years.
Ayush’s father’s age at the time of Ayush’s birth = (35 – 10) years = 25 years.
Therefore Ayush’s father’s age at the time of marriage = (25 – 2) years = 23 years.
[B].
[C].
[D].
Answer: Option C
Explanation:
Since B and D are twins, so B = D.
Now, A = B + 3 and A = C – 3.
Thus, B + 3 = C – 3 D + 3 = C-3 C – D = 6.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5X = 70 or x = 14.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the number of cows be x and the number of hens be y.
Then, 4x + 2y = 2 (x + y) + 14 4x + 2y = 2x + 2y + 14 2x = 14 x = 7.
[B].
[C].
[D].
Answer: Option A
Explanation:
Clearly, we have :
A = B – 3 …(i)
D + 5 = E …(ii)
A+C = 2E …(iii)
B + D = A+C = 2E …(iv)
A+B + C + D + E=150 …(v)
From (iii), (iv) and (v), we get: 5E = 150 or E = 30.
Putting E = 30 in (ii), we get: D = 25.
Putting E = 30 and D = 25 in (iv), we get: B = 35.
Putting B = 35 in (i), we get: A = 32.
Putting A = 32 and E = 30 in (iii), we get: C = 28.
[B].
[C].
[D].
Answer: Option C
Explanation:
Clearly, we have :
B-3 = E …(i)
B + 3 = D …(ii)
A+B = D + E+10 …(iii)
B = C + 2 …(iv)
A+B + C + D + E= 133 …(v)
From (i) and (ii), we have : 2 B = D + E …(vi)
From (iii) and (vi), we have : A = B + 10 …(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B – 2) + 2B = 133 5B = 125 B = 25.
[B].
[C].
[D].
Answer: Option D
Explanation: