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Stoichiometry

A butane isomerisation process produces 70 k.mole/hr of pure iso-butane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole%). The feed stream is n-butane containing 1% impurity (mole%). The flow rate of the purge stream will be_________________?

A butane isomerisation process produces 70 k.mole/hr of pure iso-butane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole%). The feed stream is n-butane containing 1% impurity (mole%). The flow rate of the purge stream will be_________________?

A. 3 kmole/hr
B. 4 kmole/hr
C. 5 kmole/hr
D. 6 kmole/hr

A butane isomerisation process produces 70 k.mole/hr of pure iso-butane. A purge stream removed continuously, contains 85% n-butane and 15% impurity (mole%). The feed stream is n-butane containing 1% impurity (mole%). The flow rate of the purge stream will be_________________? Read More »

Stoichiometry

The molecules of a liquid which is in equilibrium with its vapor at its boiling point on an average have equal _____________ in the two phases?

The molecules of a liquid which is in equilibrium with its vapor at its boiling point on an average have equal _____________ in the two phases?

A. Potential energy
B. Intermolecular forces
C. Kinetic energy
D. Total energy

The molecules of a liquid which is in equilibrium with its vapor at its boiling point on an average have equal _____________ in the two phases? Read More »

Stoichiometry

Na2SO4. 10H2O crystals are formed by cooling 100 Kg of 30% by weight aqueous solution of Na2SO4. The final concentration of the solute in the solution is 10%. The weight of crystals is________________?

Na2SO4. 10H2O crystals are formed by cooling 100 Kg of 30% by weight aqueous solution of Na2SO4. The final concentration of the solute in the solution is 10%. The weight of crystals is________________?

A. 20
B. 32.2
C. 45.35
D. 58.65

Na2SO4. 10H2O crystals are formed by cooling 100 Kg of 30% by weight aqueous solution of Na2SO4. The final concentration of the solute in the solution is 10%. The weight of crystals is________________? Read More »

Stoichiometry

The density of a gas ‘X’ is twice that of another gas ‘Y’. If the molecular weight of gas ‘Y’ is ‘M’; then the molecular weight of the gas ‘X’ will be________________?

The density of a gas ‘X’ is twice that of another gas ‘Y’. If the molecular weight of gas ‘Y’ is ‘M’; then the molecular weight of the gas ‘X’ will be________________?

A. 2M
B. M/2
C. M
D. M/4

The density of a gas ‘X’ is twice that of another gas ‘Y’. If the molecular weight of gas ‘Y’ is ‘M’; then the molecular weight of the gas ‘X’ will be________________? Read More »

Stoichiometry

Air at a temperature of 20°C and 750 mm Hg pressure has a relative humidity of 80%. What is its percentage humidity? Vapour pressure of water at 20°C is 17.5 mm Hg?

Air at a temperature of 20°C and 750 mm Hg pressure has a relative humidity of 80%. What is its percentage humidity? Vapour pressure of water at 20°C is 17.5 mm Hg?

A. 80.38
B. 80
C. 79.62
D. 78.51

Air at a temperature of 20°C and 750 mm Hg pressure has a relative humidity of 80%. What is its percentage humidity? Vapour pressure of water at 20°C is 17.5 mm Hg? Read More »

Stoichiometry

80 kg of Na2SO4 (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na2SO4 .10H2O crystals separate out. The weight fraction of Na2SO4 in the remaining solution is_________________?

80 kg of Na2SO4 (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na2SO4 .10H2O crystals separate out. The weight fraction of Na2SO4 in the remaining solution is_________________?

A. 0.00
B. 0.18
C. 0.24
D. 1.00

80 kg of Na2SO4 (molecular weight = 142) is present in 330 kg of an aqueous solution. The solution is cooled such that. 80 kg of Na2SO4 .10H2O crystals separate out. The weight fraction of Na2SO4 in the remaining solution is_________________? Read More »

Stoichiometry