A. 2:3:5
B. 8:12:15
C. 2:8:5
D. 2:7:5
If A:B = m1:n1 ; B:C = m2:n2
Then, A:B:C = (m1*m2):(n1*m2):(n1*n2)
Therefore, X:Y:Z = (2*4):(3*4):(3*5)
= 8:12:15
A. 15
B. 10
C. 8
D. 5
a:b = 3:5 5a = 3b (a+2):(b+2) = 2:3 3(a+2) = 2(b+2) 3a+6 = 2b+4 3*(3b/5) = 2b-2 9b = 10b-10 b =10
A. 1200 m²
B. 1500 m²
C. 12000 m²
D. 15000 m²
Actual length
= 30*500 cm Actual breadth
= 20*500 cm Actual area
= 30*20*500*500 = 15000 m²
A. 54 cm
B. 27 cm
C. 12 cm
D. 15 cm
Let the length and breadth be 5x cm and 4x cm.
5x*4x=180
20x²=180
x²=9,x=3 Length = 15cm Breadth = 12cm Perimeter
= 2(l+b)
= 2*27
= 54 cm
A. 16 : 2 : 3
B. 8 : 3 : 6
C. 16 : 2 : 9
D. 6 : 9 : 1
Let the profit of X be P1, that of Y be P2 and of Z be P3.
P1:P2:P3 = 20000*12 : 7500*4 : 15000*9 = 240 : 30 : 135 = 80 : 10 : 45
= 16 : 2 : 9
A. 1/3
B. 7/9
C. 5/12
D. None of these
M/P = M/N * N/O * O/P = ¾ * 5/7 * 7/9 = 5/ 12
A. 45 cm
B. 40 cm
C. 36 cm
D. 27 cm
Let the three sides be 4x,3x and 2x. 4x+3x+2x = 81 9x = 81 x = 9 Length of the largest side
= 4x = 36 cm
A. 96
B. 68
C. 72
D. 108
Let the number of boys and girls in the class be 11x and 13x. 4 boys and 8 girls join the class. Strength of the class
= 11x+13x+4+8
= 24x+12 (11x+4):(13x+8) = 4:5 5*(11x+4)=4*(13x+8) 55x+20=52x+32 3x=12 x=4 24x+12=108
A. 48
B. 42
C. 60
D. 70
7x+8x=90 15x=90 x=6 Number of boys=7x=42
A. 120
B. 80
C. 192
D. 48
If A invests amount C1 for T1 time and his of profit is P1, and B invests amount C2 for T2 time and his of profit is P2, then, C1 * T1 / C2 * T2 = P1/P2
If P is the Nasir’s of profit, then Changaz gets (240 – P)
Therefore, 6000 * 12 / 3000 * 6 = (240 – P) / P = 72/ 18 = 4
4P = (240 – P)
5P = 240
P = 48