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Problems on L.C.M and H.C.F

H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is___________?

H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is___________?

A. 180
B. 360
C. 540
D. 1260
Explanation:
4 * 27 * 3125 = 22 * 33 * 55;
8 * 9 * 25 * 7 = 23 * 32 * 52 * 7;
16 * 81 * 5 * 11 * 49 = 24 * 34 * 5 * 72 * 11
H.C.F = 22 * 32 * 5 = 180.

H.C.F of 4 * 27 * 3125, 8 * 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49 is___________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Which of the following has most number of divisors?

Which of the following has most number of divisors?

A. 99
B. 101
C. 176
D. 182
Explanation:
99 = 1 * 3 * 3 * 11; 101 = 1 * 101;
176 = 1 * 2 * 2 * 2 * 2 * 11; 182 = 1 * 2 * 7 * 13
So, divisors of 99 are 1, 3, 9, 11, 33 and 99;
divisors of 101 are 1 and 101;
divisors of 176 are 1, 2, 4, 8, 16, 22, 44, 88 and 176;
divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.

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Mathematics Mcqs, Problems on L.C.M and H.C.F

A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn’t want to mix any two drinks in a can. What is the least number of cans required?

A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn’t want to mix any two drinks in a can. What is the least number of cans required?

A. 35
B. 37
C. 42
D. 30
Explanation:
The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 80/16 = 5
Number of cans of Pepsi = 144/16 = 9
Number of cans of Sprite = 368/16 = 23
The total number of cans required = 5 + 9 + 23 = 37 cans.

A drink vendor has 80 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn’t want to mix any two drinks in a can. What is the least number of cans required? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room?

A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room?

A. 110
B. 124
C. 96
D. 117
Explanation:
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 * 432)/(48 * 48) = 13 * 9 = 117

A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?

Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?

A. 3
B. 4
C. 5
D. 6
Explanation:
Calculate the differences, taking two numbers at a time as follows:
(215-47) = 168
(365-215) = 150
(365-47) = 318
HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5.

Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?

Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?

A. 16
B. 17
C. 18
D. 19
Explanation:
Subtract the remainder 3 from each of the given numbers: (19-3)=16, (67-3)=64 and (83-3)=80. Now, find the HCF of the results 16, 64 and 80, we get 16. Thus, the greatest number is 16.

Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case?

A. 1020
B. 1026
C. 1030
D. 1022
Explanation:
Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 – 40) = 1020.
Now, add the remainder 2 that’s required. Thus, the answer is 1022.

Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F