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Problems on L.C.M and H.C.F

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is________?

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is________?

A. 75
B. 81
C. 85
D. 89
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is__________?

The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is__________?

A. 1
B. 2
C. 3
D. 4

Explanation:
Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.

The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is__________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is_________?

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is_________?

A. 101
B. 107
C. 111
D. 185
Explanation:
Let the numbers be 37a and 37b.
Then, 37a * 37 b = 4107 => ab = 3
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 * 1, 37 * 3) i.e., (1, 111).
Greater number = 111.

The product of two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is_________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is__________?

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is__________?

A. 4
B. 6
C. 8
D. 12
Explanation:
Let the required numbers be 33a and 33b.
Then, 33a + 33b = 528 => a + b = 16.
Now, co-primes with sum 16 are (1, 15), (3, 13), (5, 11) and (7, 9).
Required numbers are (33 * 1, 33 * 15), (33 * 3, 33 * 13), (33 * 5, 33 * 11), (33 * 7, 33 * 9).
The number of such pairs is 4.

The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above conditions is__________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are__________?

Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are__________?

A. 4, 8, 12
B. 5, 10, 15
C. 10, 20, 30
D. 12, 24, 36
Explanation:
Let the required numbers be x, 2x and 3x. Then, their H.C.F = x. So, x = 12.
The numbers are 12, 24, 36.

Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are__________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 * 35 * 52 * 72. The third number is___________?

H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 * 35 * 52 * 72. The third number is___________?

A. 22 * 35 * 72
B. 22 * 53 * 72
C. 25 * 52 * 72
D. 23 * 35 * 72
Explanation:
3240 = 23 * 34 * 5; 3600 = 24 * 32 * 52
H.C.F = 36 = 22 * 32
Since H.C.F is the product of lowest powers of common factors, so the third number must have (22 * 32 ) as its factor.
Since L.C.M is the product of highest powers of common prime factors, so the third number must have 35 and 72 as its factors.
Third number = 22 * 35 * 72

H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 * 35 * 52 * 72. The third number is___________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Find the lowest common multiple of 24, 36 and 40.

Find the lowest common multiple of 24, 36 and 40.

A. 120
B. 240
C. 360
D. 480
Explanation:
2 24 – 36 – 40
——————–
2 12 – 18 – 20
——————–
2 6 – 9 – 10
——————-
3 3 – 9 – 5
——————–
1 – 3 – 5
L.C.M = 2 * 2 * 2 * 3 * 3 * 5 = 360.

Find the lowest common multiple of 24, 36 and 40. Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F