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Problems on L.C.M and H.C.F

LCM of two numbers is 138. But their (Greatest common divisor) GCD is 23. The numbers are in a ratio 1:6. Which is the largest number amongst the two?

LCM of two numbers is 138. But their (Greatest common divisor) GCD is 23. The numbers are in a ratio 1:6. Which is the largest number amongst the two?

A. 46
B. 138
C. 69
D. 23

LCM of two numbers is 138. But their (Greatest common divisor) GCD is 23. The numbers are in a ratio 1:6. Which is the largest number amongst the two? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Greatest Common Divisor of two numbers is 8 while their Least Common Multiple is 144. Find the other number if one number is 16.

Greatest Common Divisor of two numbers is 8 while their Least Common Multiple is 144. Find the other number if one number is 16.

A. 108
B. 96
C. 72
D. 36

Greatest Common Divisor of two numbers is 8 while their Least Common Multiple is 144. Find the other number if one number is 16. Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________?

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________?

A. 123
B. 127
C. 235
D. 305
Explanation:
Required number = H.C.F. of (1657 – 6) and (2037 – 5)= H.C.F. of 1651 and 2032 = 127.

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is_________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point?

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point?

A. 26 min 18 sec
B. 42 min 36 sec
C. 45 min
D. 46 min 12 sec
L.C.M of 252, 308 and 198 = 2772
So, A, B and C will again meet at the starting point in 2772 sec, i.e., 46 min 12 sec.

A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds, all starting at the same point. After what time will they meet again at the starting point? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:

A. 3
B. 13
C. 23
D. 33
Explanation:
L.C.M of 5, 6, 4 and 3 = 60.
On dividing 2496 by 60, the remainder is 37. Number to be added = 60 – 37 = 23.

The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The least number of four digits which is divisible by 15, 25, 40 and 75 is_________?

The least number of four digits which is divisible by 15, 25, 40 and 75 is_________?

A. 9000
B. 9400
C. 9600
D. 9800

Explanation:
Greatest number of 4 digits is 9999. L.C.M of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399. Required number = 9999 – 399 = 9600

The least number of four digits which is divisible by 15, 25, 40 and 75 is_________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is_________?

The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is_________?

A. 30/7
B. 30/98
C. 60/147
D. 50/294
Explanation:
Required fraction = L.C.M of 6/7, 5/14, 10/21
= (L.C.M of 6, 5, 10) / (H.C.F of 7, 14, 21) = 30/7

The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is_________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?

A. 196
B. 630
C. 1260
D. 2520
Explanation:
L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630.

What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F