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Problems on L.C.M and H.C.F

An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?

A. 3
B. 4
C. 5
D. 6
HCF of 4956, 3894 = 354
(4956 – 3894)/354 = 3

An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work?

A. 39
B. 40
C. 37
D. 35
Explanation:
HCF of 1189, 1073 = 29
1073/29 = 37

A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?

A. 700,400
B. 820,360
C. 800,500
D. 820,369

In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is_______?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is_______?

A. 36
B. 66
C. 132
D. 264
Explanation:
12 * 396 = 36 * x
x = 132

HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is_______? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?

A. 5 min
B. 5.5 min
C. 5.2 min
D. None

Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is________?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is________?

A. 1994
B. 1494
C. 1349
D. 1496
LCM = 1400
1400 – 6 = 1394

The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is_______?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is_______?

A. 31
B. 41
C. 51
D. 61
Explanation:
LCM = 30 => 30 + 1 = 31

A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is_______? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F

The smallest number when increased by ” 1 ” is exactly divisible by 12, 18, 24, 32 and 40 is__________?

Mathematics Mcqs, Problems on L.C.M and H.C.F /
The smallest number when increased by ” 1 ” is exactly divisible by 12, 18, 24, 32 and 40 is__________?

A. 1439
B. 1440
C. 1459
D. 1449
Explanation:
LCM = 1440
1440 – 1 = 1439

The smallest number when increased by ” 1 ” is exactly divisible by 12, 18, 24, 32 and 40 is__________? Read More »

Mathematics Mcqs, Problems on L.C.M and H.C.F