Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
= (7C3 x 4C2) | |||||||||
|
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= 210. |
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
Number of ways of arranging 5 letters among themselves |
= 5! |
= 5 x 4 x 3 x 2 x 1 | |
= 120. |
Required number of ways = (210 x 120) = 25200.
Video Explanation: https://youtu.be/dm-8T8Si5lg