A. 18 3/4 %
B. 20 %
C. 16 3/4 %
D. 19 %
Explanation:
Required % = (9/48 × 100)% = 75/4 % = 18 ¾ %
A period of 4 hrs 30 min is what percent of a day? Read More »
Mathematics Mcqs, Percentage Mcqs A. does not change
B. decreased by 1 %
C. increased by 1 %
D. None of these
Explanation:
Let the given number be x
Increased Number = (110% of x)
= (110/100 × x) = (11x/10)
Finally reduced number = (90 % of 11x/10)
= (90/100 × 11x/10) = 99x/100
Decrease = (x – 99x/100) = x/100
Decrease % = (x/100 × 1/x × 100)% = 1 %
When a number is first increased by 10 % and then reduced by 10 % the number:__________? Read More »
Mathematics Mcqs, Percentage Mcqs A. 2:5
B. 4:5
C. 6:7
D. 3:5
Explanation:
Let the third number be x.
Then 1st number = 120% of x = (120/100 × x) = 6x/5
2nd number = 150 % of x = (150/100 × x) = 3x/2
Ratio of these numbers = 6x/5 : 3x/2 = 12: 15 = 4 : 5
Two number is first increased by 10 % and then reduced by 10 % the number:__________? Read More »
Mathematics Mcqs, Percentage Mcqs A. 25 %
B. 55%
C. 40.5 %
D. 56.25 %
Explanation:
Let the side of the square be x units.
Then it’s area = x2 sq. Units
Side of new square = 125 % of x = (125/100 × x)units = 5x/4 units
New area = (5x/4 × 5x/4)sq.units = 25×2/16 Sq.units
Increase in area = (25×2/16 – x2) = 9×2/16 Sq.Units
Increase % = (9×2/16 × 1/x2 × 100)%
= 225/4 % = 56.25 %
If the side of a square is increased by 25 %. Then its area is increased by:__________? Read More »
Mathematics Mcqs, Percentage Mcqs A. 65 %
B. 70 %
C. 80 %
D. 60%
Explanation:
Total Area of the Paper = (30 × 15) Sq.cm = 450 Sq.cm
Area Used = [(30-5)×(15-2.5) ]Sq.cm
= (25 × 12.5) Sq.cm = (25 x 25/2) Sq.cm = 625/2 cm2
Percentage are Used by = (625/2× 1/450×100) %
= 69.4 % = 70 % nearly
A. neither increased nor decreased
B. increased by 1 %
C. decreased by 1 %
D. decreased by 10 %
Explanation:
Let original length = l units and original breadth = b units
Then original Area = lb sq. Units
New length = (110/100 l) units = (11 l)/10 units
New breadth = (90/100 b) units = (9 l)/10 units
New area = (11l/10 × 9b/10) sq. Units = 99lb/100 sq. units
Decrease in area = (lb- 99lb/100)sq units = lb/100 sq. units
Decrease in area = (lb/100 × 1/lb ×100) % = 1 %
Decrease by = 1 %
A. 6 %
B. 7 %
C. 8 %
D. 9 %
Explanation:
AC = 3cm, CB = (5 – 3)cm = 2 cm
New length AC = 106 % of 3 cm
= (106/100 ×3) cm = 3.18 cm.
New length CB = (5 – 3.18) cm = 1.82 cm
CB Decreased on 2cm = (2 – 1.82)cm = 0.18cm
CB Decrease % = (0.18/2 ×100) % = 9 %
A. Rs. 14000
B. Rs 16000
C. Rs. 18000
D. Rs. 12400
Explanation:
10/100 × B = 20/100 × c
=>B = 2c =>B = (2 × 2000) = 4000
5/100 × A = 5/100 × B =>A = 3B = (3 × 4000) = 12000
(A + B + C) = Rs (12000 + 4000 + 2000) = Rs. 18000
A. Rs. 15
B. Rs. 12
C. Rs. 10
D. Rs. 8
A. 200 gm
B. 150 gm
C. 50 gm
D. 10 gm
