A. 11. 6 %
B. 60 %
C. 76. 4 %
D. None of these
Explanation:
Total votes = (1136 + 7636 + 11628) = 20400
Required % = (11628/20400 × 100)% = 57%
A. 11. 6 %
B. 60 %
C. 76. 4 %
D. None of these
Explanation:
Total votes = (1136 + 7636 + 11628) = 20400
Required % = (11628/20400 × 100)% = 57%
A. 25000
B. 33000
C. 35000
D. 40000
Explanation:
Let the number of votes enrolled be x
Votes cast = (90/100 × x) = 9x/10
Valid votes = 90% of 9x/10 = (90/100 × 9x/10) = 81x/100
Votes polled by successful candidate
= (54/100 × 81x/100) = 4374x/10000
Votes polled by defeated candidate
= (46/100 × 81x/100) = 3726x/10000
=> 4374x – 3726x = 16200000
=> x = 16200000/648 = 25000
A. 10000
B. 16400
C. 16800
D. 18000
Explanation:
Let the enrolled votes be x,
Votes cast = (75/100 × x) = 3x/4
Valid votes = (98/100 × 3x/4)
= 147x/200 75/100 × 147x/200 = 9261
=> 441x = (9261 × 800)
=> x = 16800
A. 2700
B. 2900
C. 3000
D. 3100
Explanation:
Valid votes = (80/100 × 7500) = 6000
Valid votes polled by one candidates
=(55/100 × 6000) = 3300
Valid votes polled by another candidate
= (6000 – 3300) = 2700
A. 21000
B. 2200
C. 23500
D. 27500
Explanation:
Let the total number of voters be x
Votes cast = 92 % of x = (92/100 × x) = 23x/25
Votes in favour of winning candidate = 48/100 × x
= 12x/25
Votes polled by defeated candidate = (23x/25 – 12x/25)
= 11x/25 12x/25 – 11x/25 = 1100
=> 12x – 11x = 27500
=> x = 27500
A. Rs. 20 per kg
B. Rs. 22.50 per kg
C. Rs. 25 per kg
D. Rs. 27.50 per kg
A. 989, 1501
B. 1011, 1479
C. 1401, 1089
D. 1411, 1079
Explanation:
Let the number be x and (2490 – x).
Then 6.5 % of x = 8.5 % of (2490 – x)
=> 6.5/100 × x = 8.5/100 × (2490 – x)
=> 65x/1000 = 85(2490 – x)/1000
=> 65x = (85 × 2490) – 85x
=> 150x =(85 × 2490)
=> x = 211650/150 = 1411
Hence the numbers are 1411 and (2490 – 1411) = 1079
A. 22. 5 %
B. 27.5 %
C. 32. 5 %
D. 37.5 %
Explanation:
Males = (60/100 × 1000) = 600,
females = (1000 – 600) = 400
Literate males = (20/100 × 600) = 120
Total literates = (25/100 × 1000) = 250
Female literates = (250 – 120) = 130
Required % = (130/400 × 100)% = 32.5 %
A. 68 4/7 %
B. 78 %
C. 80 %
D. 80 4/7 %
Explanation:
Total candidates = (100 + 75) = 175
Total passed = (75/100 × 100) + (60/100 × 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 × 100)%
= 480/7 % = 68 4/7 %
A. 3 ml
B. 4 ml
C. 5 ml
D. 6 ml
Explanation:
Alcohol in 9 ml lotion = (50/100 × 9)ml = 4.5ml
Water in it = (9 – 4.5)ml = 4.5ml
Let x ml of water be added to it, then 4.5/9+x × 100 = 30
=> 4.5/9+x = 30/100 = 3/10
=> 3(9+x) = 45 => 27 + 3x = 45
=> 3x = 18
=> x = 6
Water to be added = 6 ml