Two numbers X and Y are respectively 20% and 28% less than a third number Z. By what percentage is the number Y less than that of the number X?
A. 8%
B. 9%
C. 10%
D. 11%
A. 8%
B. 9%
C. 10%
D. 11%
A. 750
B. 500
C. 250
D. 125
Explanation:
Let x% candidates take both the subjects.
Therefore, Percentage of candidates who opted physics = 65.8%
And percentage of candidates who opted mathematics = 59.2%
Therefore, x =(65.8 + 59.2 – 100)%
= (125 -100)% = 25%
Also total number of candidates = 2000
Therefore, Number of candidates who opted both the subjects = 25/100 x 2000 =500
A. 70%
B. 60%
C. 40%
D. 30%
Explanation:
Total number of employees be 100
Then number of men = 6000/100 = 60
Number of women = 4000/100 = 40
Therefore, number of men drawing more than Rs. 50000 = 2400/100 = 24 men
Since the number of total employees drawing more than Rs. 50000 = 3600/100 = 36
Number of women who draw more than Rs. 50000 = 36- 24 = 12
Number of women who draw less than Rs. 50000 = 40 -12 = 28
Therefore, Percentage of the women who draw less than Rs. 50000 per year = 28/40 x 100% = 70%
A. 24000
B. 30000
C. 54000
D. 60000
Explanation:
Total population = 300000
Total number of males = 180000
Total literates = 5% of total population = 150000
Number of literate males = 70% of males = 126000
A. 8
B. 10
C. 15
D. 16
Explanation:
Let the marks of each question be 10
Total marks got by the candidate = 8 x 5 =40 marks
40% = 40 : 100 = 100
Therefore, Total number of questions = 100/10 =10
A. 10%
B. 15%
C. 20%
D. 25%
A. Success rate is higher for women
B. Overall success rate is below 50%
C. More men cleared the examination than women
D. Both ‘A’ and ‘B’
Explanation:
Let there are 100 persons in which 60 men and 40 women number of men who cleared the qualifying test
= 70 x 60/100 = 42
Number of women who cleared the qualifying test
= 40 x ¾ = 30
Number of men who get success in final test
= 42 x 4/5 = 33.6
Number of women who get success in final test
= 30 x 70/100 = 21
Hence more men cleared the examination than a woman.
A. 10 20/23 %
B. 13 1/23 %
C. 16 2/3 %
D. 15 %
Explanation:
Reduction % in consumption
= {r/(100+r) ×100} % =(15/115 × 100)%
= 300/23 % = 13 1/23 %
A. 10/19
B. 5/9
C. 9/5
D. 19/7
A. Rs. 8000
B. Rs 10000
C. Rs. 18000
D. Rs. 81000
Explanation:
Value after 2 Years = Rs[100000 × (1 – 10/100)2]
= Rs (100000 × 0.9 × 0.9) = Rs 81000