In what ratio must water be mixed with milk to gain 16 2/3 % by selling the mixture at cost price?
A. 1:6
B. 2:3
C. 4:3
D. 6:1
A. 1:6
B. 2:3
C. 4:3
D. 6:1
A. 3:2
B. 3:4
C. 3:5
D. 4:5
A. 1:3
B. 2:3
C. 3:4
D. 4:5
A. 72
B. 72.9
C. 73.8
D. 74.7
E. None of these
Explanation:
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]2 (90) = 72.9 litres.
A. 16 : 5
B. 14 : 5
C. 16 : 7
D. 19 : 5
E. None of these
Explanation:
Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5.
A. 3/5
B. 1/2
C. 1/4
D. 2/7
A. Rs. 18
B. Rs. 18.50
C. Rs. 19
D. Rs. 19.50
A. 3 : 2
B. 3 : 4
C. 3 : 5
D. 4 : 5
A. 2:5
B. 1:5
C. 3:5
D. 4:5
A. 25 liters
B. 28 litres
C. 30 liters
D. 35 liters
Explanation:
Total cost price =Rs(40 x 7/2) = Rs.140
Cost per litre =Rs.2,
Total quantity = 140/2 = 70 Litres.
Water to be added =(70-40) =30 Litres.