A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
A. 5 km
B. 5.5 km
C. 6 km
D. 6.5 km
Average speed = ( 2 X 3 X 2/3 + 2 ) km/ hr = 12/5 km/ hr. Distance travelled = ( 12/5 X 5 )km = 12 km. So Distance between house and school = ( 12/2 )km = 6 km.
A. 6 hrs 21 min
B. 6 hrs 24 min
C. 6 hrs 27 min
D. 6 hrs 30 min
Time taken to cover 600 km = ( 600/100 ) hrs = 6 hrs. Number of stoppages = ( 600/75 – 1 ) = 7 Total time of stoppage = (3 x 7) min = 21 min. Hence, total time taken = 6 hrs 21 min.
A. 7.42 a.m.
B. 7.48 a.m.
C. 8.10 a.m.
D. 8.30 a.m.
A. 220 km
B. 224 km
C. 230 km
D. 234 km
A. 45 metres
B. 55 metres
C. 450 metres
D. Cannot be determined
A. 10 min
B. 11 min 20 sec
C. 13 min
D. 13 min 20 sec
Speed = (10 X 60/12 ) km/hr = 50 km/hr. New speed = (50 – 5) km / hr = 45 km /hr. So Time taken = ( 10/45 ) hr = ( 2/9X 60 )min 131/3 min = 13 min 20 sec.
A. 1.4
B. 1.5
C. 1.7
D. 1.9
A. 1.4 m
B. 2.8 m
C. 14 m
D. None of these
A. 12 kg
B. 60 kg
C. 72 kg
D. 96 kg
Volume of water displaced = (3 X 2 X 0.01) m3 = 0.06 m3.
Mass of man = Volume of water displaced X Density of water
= (0.06 X 1000) kg = 60 kg.
A. the volume of the box
B. twice the volume of the box
C. the square of the volume of the box
D. the cube root of the volume of the box
Let length = 1, breadth = b and height = h. Then,
Product of areas of 3 adjacent faces = (lb x bh x 1h) = (lbh)2 = (Volume)2.