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Mathematics Mcqs

Of the 1000 inhabitants of a town 60 % are males of whom 20 % are literate. If of all the inhabitants 25 % are literate. Then what percent of the females of the town are literate?

Of the 1000 inhabitants of a town 60 % are males of whom 20 % are literate. If of all the inhabitants 25 % are literate. Then what percent of the females of the town are literate?

A. 22. 5 %
B. 27.5 %
C. 32. 5 %
D. 37.5 %
Explanation:
Males = (60/100 × 1000) = 600,
females = (1000 – 600) = 400
Literate males = (20/100 × 600) = 120
Total literates = (25/100 × 1000) = 250
Female literates = (250 – 120) = 130
Required % = (130/400 × 100)% = 32.5 %

Of the 1000 inhabitants of a town 60 % are males of whom 20 % are literate. If of all the inhabitants 25 % are literate. Then what percent of the females of the town are literate? Read More »

Mathematics Mcqs, Percentage Mcqs

In two successive years, 100 and 75 students of a school appeared at the final examination. Respectively 75 % and 60 % of them passed. The average rate of pass is:_________?

In two successive years, 100 and 75 students of a school appeared at the final examination. Respectively 75 % and 60 % of them passed. The average rate of pass is:_________?

A. 68 4/7 %
B. 78 %
C. 80 %
D. 80 4/7 %
Explanation:
Total candidates = (100 + 75) = 175
Total passed = (75/100 × 100) + (60/100 × 75)
= (75 + 45) = 120
Therefore Pass % = (120/175 × 100)%
= 480/7 % = 68 4/7 %

In two successive years, 100 and 75 students of a school appeared at the final examination. Respectively 75 % and 60 % of them passed. The average rate of pass is:_________? Read More »

Mathematics Mcqs, Percentage Mcqs

The quality of water that should be added to reduce 9 ml. Lotion containing 50 % alcohol to a lotion containing 30 % alcohol is_________?

The quality of water that should be added to reduce 9 ml. Lotion containing 50 % alcohol to a lotion containing 30 % alcohol is_________?

A. 3 ml
B. 4 ml
C. 5 ml
D. 6 ml
Explanation:
Alcohol in 9 ml lotion = (50/100 × 9)ml = 4.5ml
Water in it = (9 – 4.5)ml = 4.5ml
Let x ml of water be added to it, then 4.5/9+x × 100 = 30
=> 4.5/9+x = 30/100 = 3/10
=> 3(9+x) = 45 => 27 + 3x = 45
=> 3x = 18
=> x = 6
Water to be added = 6 ml

The quality of water that should be added to reduce 9 ml. Lotion containing 50 % alcohol to a lotion containing 30 % alcohol is_________? Read More »

Mathematics Mcqs, Percentage Mcqs

Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh?

Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh?

A. 1000 kg
B. 1100 kg
C. 1125 kg
D. 1225 kg
Explanation:
Let the weight of fresh grapes be x kg
Quantity of water in it = (80/100 × x)kg = 4x/5 kg
Quantity of pulp in it = (x – 4x/5)kg = x/5 kg
Quantity of water in 250 kg dry grapes
= (10/100 × 250)kg = 25kg
Quantity of pulp in it = (250 – 25)kg = 225 kg
Therefore, x/5 = 225
=> x = 1125

Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh? Read More »

Mathematics Mcqs, Percentage Mcqs

Fresh fruit contains 68 % water and dry fruit contains 20 % water. How much dry fruit can be obtained from 100 kg of fresh fruits?

Fresh fruit contains 68 % water and dry fruit contains 20 % water. How much dry fruit can be obtained from 100 kg of fresh fruits?

A. 32 kg
B. 40 kg
C. 52 kg
D. 80 kg
Explanation:
Quantity of water in 100kg of fresh fruits =(68/100 × 100)kg
Quantity of pulp in it = (100 – 68)kg = 32 kg
Let the dry fruit be x kg
Water in it = (20/100 × x)kg = x/5 kg
Quantity of pulp in it = (x – x/5)kg = 4x/5 kg
Therefore, 4x/5 = 32 => x = 160/4 = 40 kg

Fresh fruit contains 68 % water and dry fruit contains 20 % water. How much dry fruit can be obtained from 100 kg of fresh fruits? Read More »

Mathematics Mcqs, Percentage Mcqs

If the numerator of a fraction is increased by 140 % and the denominator is increased by 150 % the resultant fraction is 4/15 what is the original fraction?

If the numerator of a fraction is increased by 140 % and the denominator is increased by 150 % the resultant fraction is 4/15 what is the original fraction?

A. 3/5
B. 5/16
C. 2/9
D. None of these

If the numerator of a fraction is increased by 140 % and the denominator is increased by 150 % the resultant fraction is 4/15 what is the original fraction? Read More »

Mathematics Mcqs, Percentage Mcqs

In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is_________?

In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is_________?

A. 8. 35 %
B. 7.15 %
C. 8.15 %
D. 6. 25%
Explanation:
Let length = x units and breadth = Y units
Then actual area = xy sq.units
Length shown = (105/100 × x)units = 21x/20 units;
Breadth shown = (103/100 × Y)
Calculated area = (21x/20 × 103y/100)sq.units
= 2163xy/2000 sq.units
Error = (2163xy/2000 – xy)
= 163xy/2000
Error % = (163xy/2000 × 1/xy × 100)%
= 163/20 % = 8.15 %

In measuring the sides of a rectangle errors of 5 % and 3 % in excess are made. The error percent in the calculates area is_________? Read More »

Mathematics Mcqs, Percentage Mcqs

The price of petrol is increased by 25 %. By how much percent a car owner should reduce his consumption of petrol. So that expenditure on petrol would not be increased?

The price of petrol is increased by 25 %. By how much percent a car owner should reduce his consumption of petrol. So that expenditure on petrol would not be increased?

A. 25 %
B. 30 %
C. 50 %
D. 20 %
Explanation:
Reduction % in consumption = {r/(100+ r) × 100}% = (25/125 × 100)% = 20%

The price of petrol is increased by 25 %. By how much percent a car owner should reduce his consumption of petrol. So that expenditure on petrol would not be increased? Read More »

Mathematics Mcqs, Percentage Mcqs

If the price of the eraser is reduced by 25% a person buy 2 more erasers for a rupee. How many erasers available for a rupee?

If the price of the eraser is reduced by 25% a person buy 2 more erasers for a rupee. How many erasers available for a rupee?

A. 8
B. 6
C. 4
D. 2
Explanation:
Let n erasers be available for a rupee
Reduced Price = (75/100 × 1) = Re ¾
¾ rupee fetch n erasers = 1 Rupee will fetch (n × 4/3) erasers
Therefore, 4n/3 = n +2 => 4n = 3n +6 => n =6

If the price of the eraser is reduced by 25% a person buy 2 more erasers for a rupee. How many erasers available for a rupee? Read More »

Mathematics Mcqs, Percentage Mcqs

In a school, 40 % of the students play football and 50 % play cricket. If 18 % of the students play neither football nor cricket, the percentage of students playing both is________?

In a school, 40 % of the students play football and 50 % play cricket. If 18 % of the students play neither football nor cricket, the percentage of students playing both is________?

A. 40 %
B. 32 %
C. 22 %
D. 8 %
Explanation:
Let A = set of students who play football and
B = set of students play cricket.
Then n(A) = 40, n (B) = 50 and
n(A U B) = (100 – 18) = 82
n(A U B) = n(A) + n(B) – n(A ∩ B)
n(A∩B) = n(A) + n(B) – n(AUB) = (40 + 50 -82) = 8
Percentage of the students who play both = 8%

In a school, 40 % of the students play football and 50 % play cricket. If 18 % of the students play neither football nor cricket, the percentage of students playing both is________? Read More »

Mathematics Mcqs, Percentage Mcqs