One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
A. 81 min.
B. 108 min.
C. 144 min.
D. 192 min.
A. 81 min.
B. 108 min.
C. 144 min.
D. 192 min.
A. 16 hrs
B. 20 hrs
C. 25 hrs
D. 40 hrs
Work done by leak in 1 hour = (1/8 – 1/10) = 1/40
The leak will empty the cistern in 40 hours.
A. 5 Hours
B. 6 Hours
C. 7 Hours
D. 8 Hours
Explanation:
Net filling in 1 hour = (1/2 – 1/3) = 1/6
Time taken to fill the cistern = 6 hours
A. 8
B. 10
C. 16
D. 24
Explanation:
Part filled by insert in 1 hour = 1/8
Part emptied by outlet in 1 hour = 1/16
Net filling in 1 hour = (1/8 – 1/16) = 1/16
Time taken to fill the tank = 1/16 hour= 16 hours
A. 10
B. 12
C. 14
D. 16
Explanation:
Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 – 1/3 = 2/3
(A + B)’s 1 hour work = 2/21
C’s 1 hour work = [(A + B + C)’s 1 hour work – (A + B)’s 1 hour work]
= (1/6 – 2/21) = 1/14
C alone can fill the tank in 14 hours.
A. 5 min
B. 9 min
C. 10 min
D. 15 min
Explanation:
Let B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 – x) min = 1.
x(2/75 + 1/45) + (30- x) 2/75 = 1
11x + 180 – 6x = 225 => x = 9
A. 60 gallons
B. 100 gallons
C. 120 gallons
D. 180 gallons
Explanation:
Work done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40
Volume of 1/40 part = 3 gallons
Volume of whole = 3 * 40 = 120 gallons.
A. 6 hrs
B. 6 2/3 hrs
C. 7 hrs
D. 7 1/2 hrs
Explanation:
(A + B)’s 1 hour work = (1/12 + 1/15) = 3/20
(A + C)’s 1 hour work = (1/12 + 1/20) = 2/15
Part filled in 2 hrs = (3/20 + 2/15) = 17/60
Part filled in 6 hrs = 3 * 17/60 = 17/20
Remaining part = 1 – 17/20 = 3/20
Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour.
Total time taken to fill the tank = (6 + 1) = 7 hrs.
A. 15 min
B. 20 min
C. 27.5 min
D. 30 min
Explanation:
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
x/2 * 1/15 = 1 => x = 30 min.
A. 10 min 20 sec
B. 11 min 45 sec
C. 12 min 30 sec
D. 14 min 40 sec
Explanation:
Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15
Remaining part = 1 – 7/15 = 8/15
Part filled by B in 1 minute = 1/20
1/20 : 8/15 :: 1 ; x
x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.
The tank will be full in (4 min. + 10 min. 40 sec) = 14 min 40 sec.