A metal sheet 27 cm long 8cm broad and 1 cm thick is melted into a cube. The difference between the surface areas of two solids is__________?

A metal sheet 27 cm long 8cm broad and 1 cm thick is melted into a cube. The difference between the surface areas of two solids is__________?

A. 284 cm2
B. 286 cm2
C. 296 cm2
D. 300 cm2
Explanation:
Volume of sheet = (27 × 8 × 1)cm3 = 216 cm3

Volume of cube formed = 216 cm3

Therefore, Edge of the cube = (6 × 6 × 6)1/3 = 6 cm

Surface area of original cuboid = 2 (27 × 8 + 8 × 1 + 27 × 1) cm2 = 502 cm2

Surface area of the cube formed = [6 × (6) 2] cm2 = 216 cm2

Therefore, Difference in areas = (502 – 216)cm2= 286 cm2

If the length, breadth and the height of a cuboid are in the ratio 6: 5: 4 and if the total surface area is 33300 cm2, then length breadth and height in cms, are respectively?

If the length, breadth and the height of a cuboid are in the ratio 6: 5: 4 and if the total surface area is 33300 cm2, then length breadth and height in cms, are respectively?

A. 90, 85, 60
B. 85, 75, 60
C. 90, 75, 70
D. 90, 75,60
Explanation:
Length = 6x
Breadth = 5x
Height = 4x in cm
Therefore, 2(6x × 5x + 5x × 4x + 6x × 4x) = 33300
148×2 = 33300
=> x2 = 33300/148 = 225
=> x = 15.
Therefore, Length = 90cm,
Breadth = 75cm,
Height = 60cm
90, 75 , 60 cm