A. 5:4
B. 9:4
C. 4:5
D. 4:9
Explanation:
Let original side be x metres, then area = x2 Sq.m
New side =(150% of x)m = (150/100 × x)m =(3x/2)m
New area =(3x/2 x 3x/2)m2 = 9×2/4 m2
Required ratio of area = 9×2/4 : x2 = 9:4
A. 5:4
B. 9:4
C. 4:5
D. 4:9
Explanation:
Let original side be x metres, then area = x2 Sq.m
New side =(150% of x)m = (150/100 × x)m =(3x/2)m
New area =(3x/2 x 3x/2)m2 = 9×2/4 m2
Required ratio of area = 9×2/4 : x2 = 9:4
A. Increased by 4%
B. decreased by 4%
C. Decreased by 1%
D. Remains unchanged
Explanation:
Let length = x metres and breadth = y metres, then area =(xy)
New length =(120/100x)m = 6x/5 m
New breadth =(80/100 y)m
New area =(6x/5 x 4y/5)m2 = (24/25 xy)m2
Decreased in area =(xy – 24/25 xy)m2= xy/25 m2
Decreased % =(xy/25 x 1/xy x 100)% = 4%
A. 20%
B. 24%
C. 36%
D. 44%
Let length = x metres and breadth = y metres , then area =(xy)m2
New length = 120/100x (6x/5)m
New breadth = 120/100 y = 6y/5m
New area (6x/5 x 6y/5)m2 = (36/25 xy)m2
Increase in area = (36/25xy – xy)m2 = (11/25 xy)m2
Increase % = (11/25 xy x 1/xy x 100)% = 44%
A. Kept unchanged
B. Increased by 25%
C. Increased by 20%
D. Reduced by 20%
Explanation:
Let the length be x metres and breadth be y metres
Then it’s area =(xy)m2
New length =(125/100 x)m =(5x/4)m.
Let the new breadth be 2 metres
Then xy 5x/4 x 2 => 2 = 4/5 y
Decreased in width =(y -4/5 y) = y/5 metres
Decreased % in width =(y/5 x 1/y x 100)% = 20%
A. 45m
B. 75m
C. 135m
D. None of these
A. 30m
B. 40m
C. 50m
D. 60m
Explanation:
Each side of the square = 160/4m =40 cm
2(l+b) = 160
=> (l+b) = 80 (40) 2 –lb = 100
=> lb =(1600 – 100) = 1500 (l-b) 2 = (l+b) 2 – 4lb
= (80) 2 -4 x 1500 =(6400 -6000) = 400 (l-b) = 20
Therefore, l+b = 80, l-b =20
=> 2l =100
=> l= 50m
A. 8cm
B. 8√2cm
C. 16cm
D. 4√2cm
Explanation:
Area of given square = ½ x (diagonal) 2 = 16cm2
Area of new square =(2 x 16)cm2 = 32cm2
Let the diagonal of 2nd squared be D cm
Then ½ x D2 = 32
=> D2 =64
=> D = 8 cm
A. 10m
B. 14.14m
C. 20m
D. 25m
A. 14m
B. 18m
C. 4m
D. None of these
Explanation:
Let the breadth be x metres , then it’s length = 3x metres
=>3x × x =12
=> x2= 4
=> x =2 l=6m, b =2m
=> Perimeter = 2(6+2)m = 16m
A. 160m2
B. 180m2
C. 200m2
D. 220m2
Explanation:
Let the breadth be x metres then length = 2x metres
=> 2(2x+x) = 60
=> 6x =60
=> x =10
l = 20m and b =10m
=> Area =(20 x 10) Sq.m = 200 Sq.m