The area of a square field is 6050 Sq.m.The length of it diagonal is_________?
A. 110m
B. 112m
C. 120cm
D. 135m
The area of a square field is 6050 Sq.m.The length of it diagonal is_________? Read More »
Areas, Mathematics Mcqs A. 110m
B. 112m
C. 120cm
D. 135m
The area of a square field is 6050 Sq.m.The length of it diagonal is_________? Read More »
Areas, Mathematics Mcqs A. 25%
B. 40.5%
C. 55%
D. 56.25%
If the side of a square is increased by 25% then it’s area is increased by_________? Read More »
Areas, Mathematics Mcqs A. 125cm, 35cm
B. 126cm,32cm
C. 132cm,26cm
D. 135cm,25cm
A. 2R cm2
B. R2 cm2
C. 1/2 R2 cm2
D. 2 R2 cm2
Explanation:
Area of the largest triangle =(1/2 x 2r x r) Sq.cm =r2 Sq.cm
A. 65%
B. 70%
C. 80%
D. 60%
Explanation:
Total area =(30 x 15)Sq.cm =45 Sq.cm
Area used =[(30 – 1.25 x 2) x (15 -2.5 x2)]
=(27.5 x 10)Sq.cm =275 Sq.cm
Percentage of area used =(275/450 x 100)% =61.1%
= 60%(Approx.)
A. 0.525cm
B. 4.2cm
C. 80%
D. 60%
Explanation:
The area of two similar triangles is the ratio of the square of the corresponding heights.
Therefore , 12/48 = (2.1)2 /h2
=> h2 = 4 x (2.1)2
=> h=(2 x 2.1)=4.2 cm
A. No change
B. 8%decrease
C. 16% Decrease
D. 16%increases
Explanation:
let the height be ‘h’ and base = b, then area =(1/2 bh)sq.units
New height =(60 % of h) = (60/100 h) = 3h/5
New base =(140% of b) =(140/100 b) =(76/5)
New area =(1/2 x 7b/5 x 3h/5) Sq.units =(21/50 bh)sq.units
Decrease in area =(1/2bh – 21/50bh)= 4/50 bh
Decrease % =(4/50bh. 2/bh x 100)% =16%
A. 9cm
B. 10cm
C. 11cm
D. 12cm
Explanation:
Ratio of sides = ½ : 1/3 : ¼ = 6: 4 : 3
Side are (32 x 6/13)cm, (32 x 4/13)cm and (52 x 3/13)cm i.e…, 24 cm , 16 cm, 12 cm.
Length of smallest side = 12 cm
A. Circle
B. Square
C. Equilateral Triangle
D. Both Triangle and Square
A. 88cm2
B. 154cm2
C. 616cm2
D. 1250cm2