A. A square with an area of 36 sq.cm
B. An Equilateral Triangle with a side of 9 cm
C. A rectangle with 10 cm as length and 40 sq.cm as area
D. A circle with a radius of 4 cm
Explanation:
From Option (A), Area of Square = 36 Sq.cm
Therefore, Side of Square = √36 = 6 cm And
Perimeter of square = 4 × 6 = 24 cm
From option (B), Side of an Equilateral Triangle = 9 cm
Therefore, Perimeter of triangle = 3 × 9 = 27 cm
From Option (C), Length of rectangle , l= 10 cm And
Area of Rectangle = 40 Sq.cm
Let Breadth of Rectangle, b = 40/10 = 4 cm
Therefore, Perimeter of rectangle = 2(10 + 4) = 28 cm
From Option (D), Radius of Circle = 4 cm
Therefore Circumference of circle = 2 × 3.14 × 4 = 25.12 cm
So, Rectangle with 10 cm as length and 40 Sq.cm as an area has a greater perimeter than the rest.